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marishachu [46]
3 years ago
11

While operating a vehicle on any highway of this state, it is illegal to physically hold or support a wireless device with any p

art of the body.
True/False
Physics
1 answer:
algol133 years ago
3 0

Answer:

True

Explanation:

In Massachusetts it's illegal to drive while texting or on your phone.

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A 60-kg box is being pushed a distance of 6.2 m across the floor by a force P with arrow whose magnitude is 150 N. The force P w
Afina-wow [57]

Answer:

Explanation:

mass of box, m = 60 kg

distance, d = 6.2 m

force, P = 150 N

coefficient of kinetic friction, μk = 0.21

work done by the gravitational force, Wg = Force x distance x cos 90

Wg = 0 J

Work done by the normal force, Wn = force x distance x Cos 90

Wn = 0 J

Work done by the friction force, Wf = - μk mg d

Wf = - 0.21 x 60 x 9.8 x 6.2 = - 765.58 J

Work done by the applied force, Wp = P x d

Wp = 150 x 6.2 = 930 J

3 0
2 years ago
After six half-lives, what percentage of a radioactive sample will remain?
tatiyna
Well at the fourth half-life it would be 6.25% so if you continue calculating the answer would be B.
4 0
3 years ago
Read 2 more answers
A balloon filled with helium gas at 20°C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, whil
Marizza181 [45]

Answer:

V = 0.248 L

Explanation:

To do this, use the following equation:

P1*V1/T1 = P2*V2/T2

This equation is used to find a relation between two differents conditions of a same gas, which is this case. From this equation we can solve for V2.

Solving for V2:

V2 = P1*V1*T2/T1*P2

Temperature must be at Kelvin, so, we have to sum the temperature 273 to convert it in K.

Replacing the data we have:

V2 = 1 * 4.91 * (-196+273) / 5.2 * (20+273)

V2 = 378.07 / 1523.6

V2 = 0.248 L

7 0
3 years ago
A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir
ikadub [295]
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,

   KE1  = KE2

The kinetic energy of the system before the collision is solved below.

  KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
  KE1 = 6125 g cm²/s²

This value should also be equal to KE2, which can be calculated using the conditions after the collision.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x from the equation is 17.16 cm/s.

Hence, the answer is 17.16 cm/s. 
6 0
3 years ago
Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca
LenKa [72]

Answer:gjv

Explanation:

4 0
2 years ago
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