Question

What is the equation of the line passing through the points (2, –1) and (5, –10) in slope-intercept form?

Answer 1

(2,-1)(5,-10)
slope = (-10 - (-1) / (5 - 2) = -9/3 = -3

y = mx + b
slope(m) = -3
use either of ur points....(2,-1)...x = 2 and y = -1
now we sub and find b, the y int
-1 = -3(2) + b
-1 = -6 + b
-1 + 6 = b
5 = b

so ur equation is : y = -3x + 5 <==