What is the equation of the line passing through the points (2, –1) and (5, –10) in slope-intercept form?
1 answer:
(2,-1)(5,-10) slope = (-10 - (-1) / (5 - 2) = -9/3 = -3 y = mx + b slope(m) = -3 use either of ur points....(2,-1)...x = 2 and y = -1 now we sub and find b, the y int -1 = -3(2) + b -1 = -6 + b -1 + 6 = b 5 = b so ur equation is : y = -3x + 5 <==
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