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dalvyx [7]
3 years ago
6

Which situations describe an elastic collision?

Physics
2 answers:
Solnce55 [7]3 years ago
6 0

Answer:

Option (1)

Explanation:

There are two types of collision.

1. Elastic collisions

2. Inelastic collisions

The conditions for elastic collisions are given below:

a. the momentum is conserved.

b. kinetic energy is conserved.

c. all the forces during the collision are conservative in nature.

The conditions for inelastic collisions are given below:

a. the momentum is conserved.

b. the mechanical energy is conserved.

c. all or some of the forces are non conservative in nature.

When the two glass marbles strikes and bounce off each other, the momentum and kinetic energy both are conserved so it is the example of elastic collision.

V125BC [204]3 years ago
5 0
Elastic collisions are collisions in which both momentum and kinetic energy are conserved. I think the correct answer from the choices listed above is option A. Two <span>glass marbles bounce off each other is an example of an elastic collision. Hope this answers the question.

I hope this helps! <3
</span>
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Two blocks joined by a string have masses of 6 and 9 kg. They rest on a frictionless horizontal surface. A 2nd string, attached
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Answer:

12N

Explanation:

Suppose the string mass is negligible, the total mass of the 2 block system is 6 + 9 = 15 kg

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So both blocks would have the same acceleration, however, the force acting on the 6kg block would have a magnitude of

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3 years ago
If there are two photons with different energies, the one that has a higher energy (a) has the higher frequency (b) has the high
kozerog [31]

Answer:

(a) has the highest frequency

Explanation:

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Whereby this formula shows us that energy of a photon is directly proportional to its frequency

So hence if the energy is high then the frequency of the photon is also high

3 0
3 years ago
A sprinter accelerates from rest to 10.0 m/s in 1.35 s l. What is her acceleration?
ale4655 [162]

Answer:

dsfsdfgfdsggfgsgsfsfgfsgffsfgfgfgf

Explanation:

sgdfggsfdsgfgsgsmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

8 0
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A 0.750 kg block is attached to a spring with spring constant 13.0 N/m . While the block is sitting at rest, a student hits it w
trapecia [35]

To solve this problem we will apply the concepts related to energy conservation. From this conservation we will find the magnitude of the amplitude. Later for the second part, we will need to find the period, from which it will be possible to obtain the speed of the body.

A) Conservation of Energy,

KE = PE

\frac{1}{2} mv ^2 = \frac{1}{2} k A^2

Here,

m = Mass

v = Velocity

k = Spring constant

A = Amplitude

Rearranging to find the Amplitude we have,

A = \sqrt{\frac{mv^2}{k}}

Replacing,

A = \sqrt{\frac{(0.750)(31*10^{-2})^2}{13}}

A = 0.0744m

(B) For this part we will begin by applying the concept of Period, this in order to find the speed defined in the mass-spring systems.

The Period is defined as

T = 2\pi \sqrt{\frac{m}{k}}

Replacing,

T = 2\pi \sqrt{\frac{0.750}{13}}

T= 1.509s

Now the velocity is described as,

v = \frac{2\pi}{T} * \sqrt{A^2-x^2}

v = \frac{2\pi}{T} * \sqrt{A^2-0.75A^2}

We have all the values, then replacing,

v = \frac{2\pi}{1.509}\sqrt{(0.0744)^2-(0.750(0.0744))^2}

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7 0
3 years ago
5 description of a motion​
yuradex [85]

Answer:

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Explanation:

HOPE IT HELPS

8 0
3 years ago
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