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dalvyx [7]
3 years ago
6

Which situations describe an elastic collision?

Physics
2 answers:
Solnce55 [7]3 years ago
6 0

Answer:

Option (1)

Explanation:

There are two types of collision.

1. Elastic collisions

2. Inelastic collisions

The conditions for elastic collisions are given below:

a. the momentum is conserved.

b. kinetic energy is conserved.

c. all the forces during the collision are conservative in nature.

The conditions for inelastic collisions are given below:

a. the momentum is conserved.

b. the mechanical energy is conserved.

c. all or some of the forces are non conservative in nature.

When the two glass marbles strikes and bounce off each other, the momentum and kinetic energy both are conserved so it is the example of elastic collision.

V125BC [204]3 years ago
5 0
Elastic collisions are collisions in which both momentum and kinetic energy are conserved. I think the correct answer from the choices listed above is option A. Two <span>glass marbles bounce off each other is an example of an elastic collision. Hope this answers the question.

I hope this helps! <3
</span>
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If you lived on the Moon, would you see Earth go through phases? If so, would the sequence of phases be the same as those of the
marissa [1.9K]

Answer:

yes; yes

Explanation:

Phases of the moon refers to the shapes of the moon due to the lit part of it visible from the Earth. On a new moon day, the moon comes between the sun and the earth such that the lit portion is not visible from the Earth. On a full moon day, the earth comes between the sun and the moon and the whole lit part is visible.

When one would view the earth from the moon, the earth would also be visible as going through the phases. The order would be reversed. Understand this with the following example, On a new moon day, the Earth would be visible completely lit from the moon. So it will be full Earth day on the moon. On a full moon day, the lit side of the Earth would be completely away and hence, from the moon, new earth would be there.

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3 years ago
Daniel wants to find out if he can notice the difference in light intensity when he adds some lit candles to a set of 50 lit can
nexus9112 [7]

Answer:

5

Explanation:

The light intensity may be defined as the strength of the light or the magnitude of its brightness that a source of light can produce.

The light threshold is the minimum intensity of the light that our eye can detect and the ability to adapt to darkness.

In the context, Daniel wishes to find if can notice the difference in the intensity of the light when he add 5 candles to the set of 50 candles.

He noticed that when he added 5 candles, he could notice the difference in the intensity and when he added less than 5 candles to the set of 50 candles he could not detect.

Thus, the difference threshold for Daniel to detect the change in the intensity of the light is 5 candles.

3 0
4 years ago
Which term describes the time it takes for an object to complete one full cycle of motion on a spring?
Sav [38]

The term period (symbol: T) describes the time it takes for an object to complete one full cycle of motion on a spring.

The formula for time is: T  = 1 / f , where f is the frequency  , f= c / λ = wave speed c (m/s) / wavelength λ (m)..

The formula describes that as the frequency of a wave increases, the time period of the wave decreases.

4 0
4 years ago
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Answer:

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3 0
3 years ago
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George has a mass of 30 kg. He sits 1.4 m from the axis of rotation of a see-saw. If Susie has a mass of 27 kg, how far from the
aivan3 [116]

Answer:

d ₂ = 1.56 m : horizontal distance from where Susie sits to the axis of rotation.

Explanation:

M = F * d   Formula (1)

F is the magnitude of said force (N)

d: distance to the axis of rotation

The direction of the moment is determined by the direction of rotation and can be assumed positive in a counterclockwise direction and negative in the clockwise direction.

Forces on the see-saw

W: Weight: in the vertical direction and down

W₁= m₁*g =  30 kg*9.8 m/s²= 294 N

W₂= m₂*g =  27 kg*9.8 m/s²= 264.6 N    

Distances of the forces to the axis of rotation

d₁ =  1.4 m :distance from where W₁ is located to the axis of rotation

d₂ :  distance from where W is located to the axis of rotation

Problem development

For static equilibrium the sum of moments around the axis of rotation is zero:

∑M =0

W₁*d₁ - W₂*d₂ = 0

W₁*d₁ = W₂*d₂

294*1.4  = 264.6*d₂

411.6= 264.6*d₂

d₂ =( 411.6) / (264.6)

d ₂= 1.56 m

3 0
4 years ago
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