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3 years ago

Which situations describe an elastic collision?

Physics

2 answers:

Solnce55 [7]3 years ago

6 0

Answer:

Option (1)

Explanation:

There are two types of collision.

1. Elastic collisions

2. Inelastic collisions

The conditions for elastic collisions are given below:

a. the momentum is conserved.

b. kinetic energy is conserved.

c. all the forces during the collision are conservative in nature.

The conditions for inelastic collisions are given below:

a. the momentum is conserved.

b. the mechanical energy is conserved.

c. all or some of the forces are non conservative in nature.

When the two glass marbles strikes and bounce off each other, the momentum and kinetic energy both are conserved so it is the example of elastic collision.

V125BC [204]3 years ago

5 0

Elastic collisions are collisions in which both momentum and kinetic energy are conserved. I think the correct answer from the choices listed above is option A. Two glass marbles bounce off each other is an example of an elastic collision. Hope this answers the question.

I hope this helps! <3

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2 years ago

A 0.00275 kg air‑inflated balloon is given an excess negative charge q1 =−3.50×10−8 C by rubbing it with a blanket. It is found

kati45 [8]

Answer:

1) $\rm q_2$ is positive.

2) $\rm q_2=4.56\times 10^{-10}\ C.$

Explanation:

The charged rod is held above the balloon and the weight of the balloon acts in downwards direction. To balance the weight of the balloon, the force on the balloon due to the rod must be directed along the upwards direction, which is only possible when the rod exerts an attractive force on the balloon and the electrostatic force on the balloon due to the rod is attractive when the polarities of the charge on the two are different.

Thus, In order for this to occur, the polarity of charge on the rod must be positive, i.e., $\rm q_2$ is positive.

Given:

Mass of the balloon, m = 0.00275 kg.
Charge on the balloon, $\rm q_1 = -3.50\times 10^{-8}\ C.$
Distance between the rod and the balloon, d = 0.0640 m.
Acceleration due to gravity, $\rm g = 9.81\ m/s^2.$

In order to balloon to be float in air, the weight of the balloom must be balanced with the electrostatic force on the balloon due to rod.

Weight of the balloon, $\rm W = mg = 0.00275\times 9.81=2.70\times 10^{-2}\ N.$

The magnitude of the electrostatic force on the balloon due to the rod is given by

$\rm F_e = \dfrac{1}{4\pi \epsilon_o}\dfrac{|q_1||q_2|}{d^2}.$

$\rm \dfrac{1}{4\pi \epsilon_o}$ is the Coulomb's constant.

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2 years ago

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2 years ago

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bazaltina [42]

Answer:

Explanation:

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