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2 years ago

Can anyone help me out with this

Mathematics

1 answer:

pishuonlain [190]2 years ago

5 0

The distance around is basically the perimeter. The perimeter is found by adding the outsides together. 5+3+4=asnwer, or D
The answer is D.

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Find the value of x and y

Marianna [84]

Answer:

What is the equation?

Step-by-step explanation:

6 0

2 years ago

The teacher concluded that there is a correlation between having a computer and having a phone. Do you agree with the teacher? E

timama [110]

Answer:

yes I agree with teacher

Step-by-step explanation:

I I think this because 1 people that have a phone and a computer are the highest group and two becauseit seems that most of the class has a phone it also seems that most of the class has a computer

3 0

3 years ago

Which equation models the problem below if c represents the number of babies whose eyes are closed? There are 12 babies in a pho

Pavel [41]

The correct answer is: 9 + c = 12

Further explanation:

Given

c = number of babies whose eyes are closed

So,

If the total number of babies are 12 then the sum of babies with eyes closed and eyes opened should be equal to 12.

As c is the number of babies with eyes closed and 9 is the number of babies with eyes opened then,

$9+c = 12$

The equation can be used to find the number of babies whose eyes are open

$9+c-9 = 12 -9\\c = 3$

Three babies have their eyes closed in the photograph.

Keywords: Linear equations, Word problems

Learn more about linear equations at:

#LearnwithBrainly

5 0

2 years ago

Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3

nlexa [21]

Answer:

$(x,y) = (5,-6)$

Step-by-step explanation:

$\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\$

$~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)$

$\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\$

$\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5$

$y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6$

$\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)$

7 0

1 year ago

How to solve a mixed number fraction

lesantik [10]

You find a common denominator (the bottom one) and then add the numerator (the top) but you don't add the denominator, you just make it the same

8 0

3 years ago