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N76 [4]
3 years ago
7

Please help me find the answer for #2

Physics
1 answer:
Anit [1.1K]3 years ago
6 0
D. a train on a straight track
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How long will it take for a car to travel 200 km if it has an average speed of 55 km/hr? ​
andreyandreev [35.5K]

Answer: Approximately 3.65 hours

Explanation:

55 km/h x 3.65 hrs = 200.75 Km/h

4 0
3 years ago
Convert the speed of light, 3.0 x 108 m/s, to km/s.
zhuklara [117]

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3 0
3 years ago
If the car’s speed decreases at a constant rate from 64 mi/h to 30 mi/h in 3.0 s, what is the magnitude of its acceleration, ass
mixas84 [53]

Answer:3.874 m/s^2

Explanation:

Given

Car speed decreases at a constant rate from 64 mi/h to 30 mi/h

in 3 sec

60mi/h \approx 26.8224m/s

34mi/h \approx 15.1994 m/s

we know acceleration is given by =\frac{velocity}{Time}

a=\frac{15.1994-26.8224}{3}

a=-3.874 m/s^2

negative indicates that it is stopping the car

Distance traveled

v^2-u^2=2as

\left ( 15.1994\right )^2-\left ( 26.8224\right )^2=2\left ( -3.874\right )s

s=\frac{488.419}{2\times 3.874}

s=63.038 m

7 0
3 years ago
A hot-air balloon is floating above a straight road. To estimate their height above the ground, the balloonists simultaneously m
Karolina [17]

Answer:

3.1 miles

Explanation:

To solve this question it is important to remember that the distance between two mile markers is approximately 1 mile

Once this is known, the question becomes very easy to solve. We make two triangle, which have the following three points

Triangle 1: Hot-Air-Balloon, Ground, Milepost 1 - With angle of depression 20

Triangle 2: Hot-Air-Balloon, Ground, Milepost 2 - With angle of depression 18

As a reminder, the angle of depression is simply the angle the balloonist's head makes with the horizontal plane to be able to see the milepost.

From this we can simply drive two formulas using the Tan function

Equation 1 - Tan(90-18) = \frac{b+1}{h}

Equation 2 - Tan(90-20) = \frac{b}{h}

Solving them simultaneously we get the value of height (h) to be 3.0852 miles or 3.1 miles

8 0
3 years ago
g If the momentum of an electron doubles, by what factor would its de Broglie wavelength be multiplied
Fynjy0 [20]

Explanation:

The de broglie wavelength is given by :

\lambda=\dfrac{h}{p}

Here,

h is Planck's constant

p is momentum

Momentum and De-Broglie wavelength has inverse relationship. If momentum of an electron double, its wavelength gets half.

5 0
3 years ago
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