g If the momentum of an electron doubles, by what factor would its de Broglie wavelength be multiplied

Physics

1 answer:

Fynjy0 [20]3 years ago

5 0

Explanation:

The de broglie wavelength is given by :

$\lambda=\dfrac{h}{p}$

Here,

h is Planck's constant

p is momentum

Momentum and De-Broglie wavelength has inverse relationship. If momentum of an electron double, its wavelength gets half.

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