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ioda
2 years ago
13

g If the momentum of an electron doubles, by what factor would its de Broglie wavelength be multiplied

Physics
1 answer:
Fynjy0 [20]2 years ago
5 0

Explanation:

The de broglie wavelength is given by :

\lambda=\dfrac{h}{p}

Here,

h is Planck's constant

p is momentum

Momentum and De-Broglie wavelength has inverse relationship. If momentum of an electron double, its wavelength gets half.

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