Question

g If the momentum of an electron doubles, by what factor would its de Broglie wavelength be multiplied

Answer 1

Explanation:

The de broglie wavelength is given by :

$\lambda=\dfrac{h}{p}$

Here,

h is Planck's constant

p is momentum

Momentum and De-Broglie wavelength has inverse relationship. If momentum of an electron double, its wavelength gets half.