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ioda
3 years ago
13

g If the momentum of an electron doubles, by what factor would its de Broglie wavelength be multiplied

Physics
1 answer:
Fynjy0 [20]3 years ago
5 0

Explanation:

The de broglie wavelength is given by :

\lambda=\dfrac{h}{p}

Here,

h is Planck's constant

p is momentum

Momentum and De-Broglie wavelength has inverse relationship. If momentum of an electron double, its wavelength gets half.

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A CD has to rotate under the readout-laser with a constant linear velocity of 1.25 m/s. If the laser is at a position 3.7 cm fro
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Explanation:

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3 years ago
A piece of styrofoam has a charge of 0.002 mC and is placed 0.5 m from a grain of salt with a charge of 0.03 nC. How much electr
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From the question,

Given: q = 0.002 mC = 2.0×10⁻⁶ C, q' = 0.03 nC = 3.0×10⁻¹¹ C, r = 0.5 m

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