Explanation:
Solution:
Let the time be
t1=35min = 0.58min
t2=10min=0.166min
t3=45min= 0.75min
t4=35min= 0.58min
let the velocities be
v1=100km/h
v2=55km/h
v3=35km/h
a. Determine the average speed for the trip. km/h
first we have to solve for the distance
S=s1+s2+s3
S= v1t1+v2t2+v3t3
S= 100*0.58+55*0.166+35*0.75
S=58+9.13+26.25
S=93.38km
V=S/t1+t2+t3+t4
V=93.38/0.58+0.166+0.75+0.58
V=93.38/2.076
V=44.98km/h
b. the distance is 93.38km
Answer:
t = S / V = 3.8E8 / 3E8 = 1.3 sec
It takes over 1 second for a radio signal to travel between the earth and the moon.
Thermometer-temperature
Wind vane -wind direction
Anemometer- both wind speed (and direction)
Hygrometer- humidity
Answer:
Explanation:
Magnetic field due to current carrying wire at a distance r from the wire is
![B=\frac{\mu_0I}{2r}---(1)](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu_0I%7D%7B2r%7D---%281%29)
In our case
![I=\frac{I_0}{2}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BI_0%7D%7B2%7D)
where,
I₀ = max current or peak current
and r = h (where h is the height of power line)
![\therefore B=\frac{\mu (I_0/2)}{2h} \\\\=\frac{\mu_0 I_0}{4h} ----(2)](https://tex.z-dn.net/?f=%5Ctherefore%20B%3D%5Cfrac%7B%5Cmu%20%28I_0%2F2%29%7D%7B2h%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B%5Cmu_0%20I_0%7D%7B4h%7D%20----%282%29)
put
h ≈ 370m
I₀ ≈ 3KA
![B= \frac{(1.26*10^-^6)(3*10^3)}{4*(370)} \\\\=2.5*10^-^6 T](https://tex.z-dn.net/?f=B%3D%20%5Cfrac%7B%281.26%2A10%5E-%5E6%29%283%2A10%5E3%29%7D%7B4%2A%28370%29%7D%20%5C%5C%5C%5C%3D2.5%2A10%5E-%5E6%20T)
Answer:6g/cm³
Explanation:density=mass/volume
D=30/5
Density of marble=6g/cm³