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olga2289 [7]
3 years ago
13

Please help, have no idea on how to solve it. Joel is pulling a sled up a hill at an angle of 30 degrees above the horizontal fo

r 5 meters. He turns 180 degrees to his right, and pulls for an additional 6 meters. What is the resultant vector of his motion?
Physics
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer:

-1m

Explanation:

I'm assuming it means that you treat the distance travelled as a displacement vector (distance of a particular direction and magnitude)

If he turns 180 degrees, he is travelling in the exact opposite direction to his original direction of travel. Therefore if he was travelling 5m in one direction, then afer his turn he travels 6m in the exact opposite direction. Opposite directions can be interpreted as the negative of the original direction.

Resultant vectors are the sum of vectors.

The sum of vectors is equal to 5m + - 6m = -1m

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Ksenya-84 [330]

Take into account that density and relative density are given by:

\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

The density of water in kg/m^3 is 1000 kg/m^3.

Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:

1 m^3 = 1000000 ml

1 kg = 1000 g

Then, you obtain the following results:

Brass:

\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}

Cooper:

\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}

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1 year ago
The parietal lobe is the portion of the cerebral cortex located below the temporal lobe.
jasenka [17]

Answer:

False

Explanation:

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3 years ago
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4 years ago
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MissTica

Answer:

Explanation:

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meters x inches/meters = inches

6.23x10^-4 m x 39.37 in./m=0.245...=2.45x10^-2

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