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olga2289 [7]
3 years ago
13

Please help, have no idea on how to solve it. Joel is pulling a sled up a hill at an angle of 30 degrees above the horizontal fo

r 5 meters. He turns 180 degrees to his right, and pulls for an additional 6 meters. What is the resultant vector of his motion?
Physics
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer:

-1m

Explanation:

I'm assuming it means that you treat the distance travelled as a displacement vector (distance of a particular direction and magnitude)

If he turns 180 degrees, he is travelling in the exact opposite direction to his original direction of travel. Therefore if he was travelling 5m in one direction, then afer his turn he travels 6m in the exact opposite direction. Opposite directions can be interpreted as the negative of the original direction.

Resultant vectors are the sum of vectors.

The sum of vectors is equal to 5m + - 6m = -1m

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uring the investigation of a traffic accident, police find skid marks 89.9 m long. They determine the coefficient of friction be
aivan3 [116]

Answer:

V_{0}=29.68m/s

Explanation:

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\sum F_{x}=ma

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-N\mu_{k}=ma

we can now solve for the acceleration, so we get:

a=\frac{-N\mu_{k}}{m}

we don't know what the normal force is, so we can find it out by analyzing the vertical forces applied to the car:

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N=W

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a=(-9.8m/s^{2})(0.5)

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a=-4.9m/s^{2}

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a=\frac{V_{f}^{2}-V_{0}^{2}}{2x}

we know the final velocity must be zero, since that's where the car got to a stop, so the formula then becomes:

a=-\frac{V_{0}^{2}}{2x}

we can now solve for the initial velocity, which yields:

V_{0}=\sqrt{-2xa}

so we can now substitute the daa we know, so we get:

V_{0}=\sqrt{-2(89.9m)(-4.9m/s^{2})}

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4 0
4 years ago
(a) A physicist performing a sensitive measurement wants to limit the magnetic force on a moving charge in her equipment to less
Free_Kalibri [48]

Answer:

q = 7.4 10⁻¹⁰ C

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Let's calculate the charge

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