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goldenfox [79]
3 years ago
12

PLS HELPPP!! ITS DUE TODAY!

Physics
1 answer:
Andrews [41]3 years ago
3 0
A is an example of physical change
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If a reaction starts with 30 grams how many should it end with?
GrogVix [38]
30 grams because of conservation
6 0
3 years ago
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Calcula el trabajo que realiza la fuerza de fregamiento sobre un cuerpo de 13kg que es desplaza una distáncia de 46 m si el coef
ZanzabumX [31]

Answer:

Los datos que tienes son:

m = 13 kg

d = 46 m

∪ = 0,45

g = 9,8 m/s²

Fr = ? 

w = ? 

Lo primero que haremos que calcular Fr

Fr = ∪mg

Fr = (0,45) (13 kg) (9,8 m/s²)

Fr = 57,33 N

Calculamos el trabajo realizado.

w = Fd

w = (57,33 N) (46 m)

w = 2637,18 Joules

Respuesta.

El trabajo realizado es 2637,18 Joules

Explanation:

3 0
3 years ago
I desperately need help with my Physics Exam I am failing this class will mark Brainliest to whoever helps the most: PART 1 (I d
GREYUIT [131]
  1. Option 2nd is correct

  1. last option is correct
6 0
2 years ago
Theresa is swinging a 4.0 kg ball on a 1.2 m long rope with a tangential speed of 1.8 m/s. What is the centripetal force exerted
Vadim26 [7]

For this case the centripetal force is given by:

F = m * (\frac{v^2}{r})

Where,

m: mass of the object

v: tangential speed

r: rope radius

Substituting values in the equation we have:

F = (4.0) * (\frac{1.8^2}{1.2})

Then, doing the corresponding calculations:

F = 10.8 N

Answer:

The centripetal force exerted on the rope is:

F = 10.8 N

5 0
3 years ago
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The steel I-beam in the drawing has a weight of 6.43 * 10^3 N and is being lifted at a constant velocity. What is the tension in
Elanso [62]

Answer:

T = 6.43 x 10^3 N

Explanation:

As we know, T = w where w = 6.43 * 10^3 N So,

T = 6.43 * 10^3 N

(If the velocity is constant tension in the string is always equals to the hanging weight where weight can be calculated by mass and gravity as w = mg)

6 0
3 years ago
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