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2 years ago

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PLS HELPPP!! ITS DUE TODAY!

1 answer:

Andrews [41]2 years ago

3 0

A is an example of physical change

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a force 2.4E2 N exists between a positive charge of 8E-5 C and a positive charge of 3E-5 C. What distance separates the charges?

Verdich [7]

The distance between the two charges is $0.3 m$

Explanation:

The electrostatic force between two charged objects is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the charges of the two objects

r is the separation between the two charges

In this problem, we are given the following:

$q_1 = 8\cdot 10^{-5} C$

$q_2 = 3\cdot 10^{-5} C$

$F=2.4\cdot 10^2 N$

Therefore, we can rearrange the equation to solve for r, the distance between the two charges:

$r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(8.99\cdot 10^9)(8\cdot 10^{-5})(3\cdot 10^{-5})}{2.4\cdot 10^2}}=0.3 m$

Learn more about electrostatic force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

6 0

2 years ago

which option below best explains why the second law of thermodynamics is not violated when heat flies from a cold freezer and in

Rainbow [258]

Explanation:

i am very sorry but you didn't give any options so i can't help you

8 0

2 years ago

The spectral distribution of the radiation emitted by a diffuse surface may be approximated as follows. HW 2 Q2 (a) What is the

Ronch [10]

Answer:

a)<em> 2000 W/m² </em><em>; </em>b) 636.94 W/m<em>².sr ; </em><em>c) </em>0.5

Explanation:

a)

The formula for calculation of total emissive power is:

Total emissive power = E = $\int\limits^\alpha_0$ E'<em>λdλ</em>

<em> </em>= $\int\limits^a_0$ (0)d<em>λ + </em> $\int\limits^b_a$ (100)d<em>λ + </em> $\int\limits^c_b$ (200)d<em>λ + </em> $\int\limits^d_c$ (100)d<em>λ </em> $\int\limits^e_d$ (0)d<em>λ</em>

<em>where a = 5; b = 10; c = 15; d = 20; e = 25</em>

<em> = 0 +100(10-5) + 200(15-10) +100(20-15) + 0</em>

<em> = 2000 W/m²</em>

b)

The formula for total intensity of radiation is:

I $_{e}$ = E/π = 200/3.14 = 636.94 W/m<em>².sr </em>

<em>c)</em>

Fo submissive power leaving the surface in range π/4 ≤θ≤π/2

[E(π/4 ≤θ≤π/2)]/E = $\int\limits^f_0$ $\int\limits^g_0$ $\int\limits^i_h$ Icosθsinθ dθdΦdλ

where f = infinity, g=2π, h=π/4, i=π/2

By simplifying, we get

= (-1/2)[cos(2π/2)-cos(2π/2)]

= -0.5(-1-0)

=0.5

8 0

3 years ago

Can electromagnetic waves travel in a vacuum? <br><br> Yes <br> Or<br> No

Sonja [21]

Answer:

Yes

Explanation:

Yes because Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

3 0

2 years ago

Copper has a modulus of elasticity of 110 GPa. A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm is pull

bearhunter [10]

Answer:

$strain = 1.4 \times 10^{-3}$

Explanation:

As we know by the formula of elasticity that

$E = \frac{stress}{strain}$

now we have

$E = 110 GPA$

$E = 110 \times 10^9 Pa$

Area = 15.2 mm x 19.1 mm

$A = 290.3 \times 10^{-6}$

now we also know that force is given as

$F = 44500 N$

here we have

stress = Force / Area

$stress = \frac{44500}{290.3 \times 10^{-6}}$

$stress = 1.53 \times 10^8 N/m^2$

now from above formula we have

$strain = \frac{stress}{E}$

$strain = \frac{1.53 \times 10^8}{110 \times 10^9}$

$strain = 1.4 \times 10^{-3}$

7 0

3 years ago