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Artemon [7]
3 years ago
10

“Gasoline boils at a relatively low temperature (about 150°C). The kerosene is removed at around 200°C, followed by diesel oil a

t 300°C and fuel oil at around 370°C.” What topic is the teacher most likely talking about?
Chemistry
1 answer:
ANEK [815]3 years ago
3 0
Well its Organic Chemistry... and is the Fractional Distillation of Crude Oil
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What are ways in controlling soil applicable in your community​
kiruha [24]

Answer:

Some methods of controlling soil erosion.

1) Planting Vegetation. This method involves planting crops with deep roots that can hold the soil in place. ...

2)Contour Farming. ...

3)Applying Mulches. ...

4)Avoiding Overgrazing. ...

5)Reforestation. ...

6)Use Plastic Sheeting. ...

7)Applying Terraseeding Method

5 0
2 years ago
Ca(MnQ4)2 molar mass
Allisa [31]

Answer:

I think u mean molar mass of ca(Mno4)2

if so it is 277.949 g/ mol

8 0
2 years ago
What observation do you expect if you react an acid and a base?
aniked [119]

"They react to neutralize the acid and base properties, producing a salt. The H(+) cation of the acid combines with the OH(-) anion of the base to form water."

8 0
2 years ago
Using the example in the above information determine the empirical formula of a compound if a sample contains 0.130 g of nitroge
olga2289 [7]

Answer: The empirical formula for the given compound is NO_2

Explanation : Given,

Mass of O = 0.370 g

Mass of N = 0.130 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.370g}{16g/mole}=0.0231moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{0.130g}{14g/mole}=0.00928moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00928 moles.

For Oxygen  = \frac{0.0231}{0.00928}=2.4\approx 2

For Nitrogen = \frac{0.00928}{0.00928}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of O : N = 2 : 1

Hence, the empirical formula for the given compound is NO_2

4 0
3 years ago
What is the density of carbon dioxide gas if 0.196g occupies a volume of 100mL?
-BARSIC- [3]

We know that the equation for density is:

D=\frac{m}{V}

where D is the density, m is the mass in grams, and V is the volume.

Given two of the variables, we can then solve for density:

D=\frac{0.196g}{100mL}= \frac{0.00196g}{mL}

So therefore, we now know that the density of carbon dioxide gas is 0.00196g/mL.

7 0
2 years ago
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