u = 5.83
Explanation:
The magnitude of a vector is
Answer:
7840 N
Explanation:
F = Nμ
F = mgμ
F = (2000 kg) (9.8 m/s²) (0.4)
F = 7840 N
Well, the quantity alone doesn't point to any one particular process.
I mean, you could get 3.826 x 10²⁶ watts of heat out of a pile of
smoldering charcoal IF the pile was big enough and you kept it
supplied with enough oxygen.
The thing about the sun is that ==> it can churn out energy at that rate
from the mass that it has, ==> it has already been doing that for so many
billions of years, and ==> it will continue doing that for so many more
billions of years in the future.
The only possible process able to accomplish that is nuclear fusion.
Answer: v = 3.57×10^6 m/s; R = 4.42×10^-3m; T = 7.78×10^-9 s
Explanation:
Magnetic force(B) = 4.60×10^-3 T
Electric force(E) = 1.64×10^4 V/m
Both forces having equal magnitude ;
Magnetic force = electric force
qvB = qE
vB = E
v = (1.64×10^4) ÷ (4.60×10^-3)
v = 3.57×10^6 m/s
2.) Assume no electric field
qvB = ma
Where a = v^2 ÷ r
R = radius
a = acceleration
v = velocity
qvB = m(v^2 ÷ R)
R = (m×v) ÷ (|q|×B)
q=1.6×10^-19C
m = 9.11×10^-31kg
R = (9.11×10^-31 * 3.57×10^6) ÷ (1.6×10^-19 * 4.6×10^-3)
R = 32.5227×10^-25 ÷ 7.36×10^-22
R = 4.42×10^-3m
3.) period(T)
T = (2*pi*R) ÷ v
T = (2* 4.42×10^-3 * 3.142) ÷ (3.57×10^6)
T = (27.775×10^-3) ÷(3.57×10^6)
T = 7.78×10^-9 s
Answer:
amount of work done = -1.77 J
Explanation:
given data
mass = 0.25 kg
speed = 5 m/s
height = 2m
to find out
amount of work done by the water on the ball bearing
solution
we get here potential energy when ball fall
potential energy = mgh
potential energy = 0.25 × 9.8 × 2
potential energy = 4.9 J
and that lose potential energy gain by kinetic energy that is express as
kinetic energy = 0.5 × m × v²
kinetic energy = 0.5 × 0.25 × 5²
kinetic energy = 3.13 J
so we get now work done that is
work done = kinetic energy - potential energy
work done = 3.13 J - 4.9 J
amount of work done = -1.77 J