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4 years ago

1. Which system has a higher random, average kinetic energy of its atoms, a glass of iced tea or a cup of hot tea?

Physics

1 answer:

natita [175]4 years ago

5 0

The average kinetic energy of the particles is higher in the hot tea, so it also has greater thermal energy then the cold tea.

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A uranium and iron atom reside a distance R = 37.50 nm apart. The uranium atom is singly ionized; the iron atom is doubly ionize

postnew [5]

Answer:

r=15.53 nm

$F=9.57\times 10^{-13}N$

Explanation:

Lets take electron is in between iron and uranium

Charge on electron $q_1= -1.602\times 10^{-19}C$

Charge on iron $q_2= 2\times 1.602\times 10^{-19}C$

Charge on uranium $q_3= 1.602\times 10^{-19}C$

We know that force between two charge

$F=K\dfrac{q_1 q_2}{r^2}$

$K=9\times 10^9\dfrac{N-m^2}{c^2}$

For equilibrium force between electron and iron should be force between electron and uranium

Lets take distance between electron and uranium is r so distance between electron and iron will be 37.5-r nm

Now by balancing the force

$K\dfrac{q_1 q_2}{r^2}=K\dfrac{q_1 q_3}{(37.5-r)^2}$

$K\dfrac{q_1q_2}{(37.5-r)^2}=K\dfrac{q_1 q_3}{r^2}$

$q_2= 2\timesq_1,q_3=q_1$

$\dfrac{q_1\times 2\timesq_1}{r^2}=\dfrac{q_1\times q_1}{(37.5-r)^2}$

So r=15.53 nm

So force

$F=9\times 10^9\dfrac{1.602\times 10^{-19}\times 1.602\times 10^{-19}}{(15.53\times 10^{-9})^2}$

$F=9.57\times 10^{-13}N$

7 0

3 years ago

Sally walks 10 meters forward and then 5 meters backwards. Which statement most accurate describes the magnitude of her displace

barxatty [35]

Sally's displacement (5m forward) is 10m less than her distance traveled (15m). <em>(B)</em>

6 0

4 years ago

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Two spherical point charges each carrying a charge of 40 μC are attached to the two ends of a spring of length 20 cm. If its spr

PolarNik [594]

Answer:

$x=3$

Explanation:

From the question we are told that:

Charge $Q=40 \mu C$

Length $L=20cm=0.20m$

Spring constant $k=120Nm^{-1}$

Generally the equation for Force between Charges is mathematically given by

$F=k\frac{q_1 q_2}{r^2}$

$F=9*10^9\frac{40*10^{-6}^2}{0.2^2^2}$

$F=360N$

Therefore

$F=kx$

$x=\frac{F}{k}$

$x=\frac{360}{120}$

$x=3$

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4 years ago

Earth's oceans have an average depth of 3800 m, a total area of 3.63 × 108 km2, and an average concentration of dissolved gold o

ratelena [41]

To determine the mass of gold dissolved in oceans, we must first know the volume of the ocean in liters. To determine its volume, we multiply the area and the depth taking note of the consistency of units. The volume would be 1.38 x 10^18 cubic meters or 1.38x10^21 liters. Then,multiplying this to the concentration, the answer would be 8 x 10^12 grams or 8 billion kg.

3 0

4 years ago

What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s2?

babunello [35]

F = m * a

F = 15 kg * 8 m/s²

F = 120 N

Answer B

hope this helps

7 0

4 years ago

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