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2 years ago

1. Which system has a higher random, average kinetic energy of its atoms, a glass of iced tea or a cup of hot tea?

Physics

1 answer:

natita [175]2 years ago

5 0

The average kinetic energy of the particles is higher in the hot tea, so it also has greater thermal energy then the cold tea.

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What is the relationship between electric motors, generators, and transformers?

KengaRu [80]

Answer:

A generator turns rotary motion into electricity. It is basically the inverse of a motor. Generally a transformer changes one voltage into another based on the number of conductor windings on each side. There are two sets of windings called the “primary” and the “secondary”.

Explanation:

6 0

3 years ago

After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of 2.85 m/s. T

motikmotik

Answer:

V' = 0.84 m/s

Explanation:

given,

Linear speed of the ball, v = 2.85 m/s

rise of the ball, h = 0.53 m

Linear speed of the ball, v' = ?

rotation kinetic energy of the ball

$KE_r = \dfrac{1}{2}I\omega^2$

I of the moment of inertia of the sphere

$I = \dfrac{2}{5}MR^2$

v = R ω

using conservation of energy

$KE_r = \dfrac{1}{2}( \dfrac{2}{5}MR^2)(\dfrac{V}{R})2$

$KE_r = \dfrac{1}{5}MV^2$

Applying conservation of energy

Initial Linear KE + Initial roational KE = Final Linear KE + Final roational KE + Potential energy

$\dfrac{1}{2}MV^2 + \dfrac{1}{5}MV^2 = \dfrac{1}{2}MV'^2 + \dfrac{1}{5}MV'^2 + M g h$

$0.7 V^2 = 0.7 V'^2 + gh$

$0.7\times 2.85^2 = 0.7\times V'^2 +9.8\times 0.53$

V'² = 0.7025

V' = 0.84 m/s

the linear speed of the ball at the top of ramp is equal to 0.84 m/s

6 0

3 years ago

If I get a spare in one frame and then roll a 1 and 5 in the next frame, what would my score for the spare be?

bonufazy [111]

The answer is letter choice B...

8 0

2 years ago

A proposed ocean thermal-energy conversion (OTEC) system is a heat engine that would operate between warm water (16°C) at the oc

LenaWriter [7]

Answer:

$3.46$ %

Explanation:

We have given cooler temperature that is $T_c$ = 6°C =273+6=279 K

And the warm temperature of water that is $T_h=16^{\circ}C=16+273=289\ K$

The maximum possible efficiency is given by $\eta =1-\frac{T_c}{T_h}$

So maximum efficiency $\eta =1-\frac{T_c}{T_h}=1-\frac{279}{289}=0.0346=3.46$ %

6 0

2 years ago

Two parallel wires are separated by 5.60 cm, each carrying 2.65 A of current in the same direction. (a) What is the magnitude of

ololo11 [35]

Explanation:

It is given that,

The separation between two parallel wires, r = 5.6 cm = 0.056 m

Current in both the wires is 2.65 A

(a) We need to find the magnitude of the force per unit length between the wires. It can be given by :

$\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi r}\\\\\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.65\times 2.65}{2\pi \times 0.056}\\\\\dfrac{F}{l}=2.5\times 10^{-5}\ N/m$

(b) As the current is in same direction, the wires will attract each other.

5 0

2 years ago