The formula we will be using is;F = G m1 m2 / r^2
F earth = 308N
F moon = G me m2 / (81.3 * 0.27^2 RE^2) = 1/5.927 G me m2 / RE^2 = F earth / 5.927 = 52 N is the force of the earth
So the answer in this question is 52 N.
'Ampere' is the unit of current. That's the rate at which
electrons travel in the circuit ... the number of electrons
every second. If you wanted the actual amount or number
of electrons, you'd need to know the length of time too.
It doesn't matter whether we're talking about a parallel or
series circuit.
Explanation:
A double replacement reaction is a reaction in which two different compounds are mixed together and both their cations and anions get exchanged with each other respectively.
When potassium bromide reacts with silver nitrate then it results in the formation of potassium nitrate and silver bromide.
The chemical reaction equation is as follows.
![KBr + AgNO_{3} \rightarrow KNO_{3} + AgBr](https://tex.z-dn.net/?f=KBr%20%2B%20AgNO_%7B3%7D%20%5Crightarrow%20KNO_%7B3%7D%20%2B%20AgBr)
Answer:
We are given x= bt +ct²
So
A. bxt= m
Because m/s*s= m
So b= m/s and c= m/s²
B.
x= bt-ct²
So at x=0 t=0
x=0 t= 2
We have
bt = ct² so t = b/c at x= 0
So b-2ct= 0
B. To find velocity we use
dx / dt = b - 2 Ct
C. At rest wen V= 0
We have t= b/2c
D. To find acceleration we use
dv / dt = - 2C
Answer:
0.98kW
Explanation:
The conservation of energy is given by the following equation,
![\Delta U = Q-W](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20Q-W)
![\dot{m}(h_1+\frac{1}{2}V_1^2+gz_1)-\dot{W} = \dot{m}(h_2+\frac{1}{2}V_2^2+gz_)](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%28h_1%2B%5Cfrac%7B1%7D%7B2%7DV_1%5E2%2Bgz_1%29-%5Cdot%7BW%7D%20%3D%20%5Cdot%7Bm%7D%28h_2%2B%5Cfrac%7B1%7D%7B2%7DV_2%5E2%2Bgz_%29)
Where
Mass flow
Specific Enthalpy (IN)
Specific Enthalpy (OUT)
Gravity
Heigth state (In, OUT)
Velocity (In, Out)
Our values are given by,
![T_i = 10\°C](https://tex.z-dn.net/?f=T_i%20%3D%2010%5C%C2%B0C)
![P_1 = 100kPa](https://tex.z-dn.net/?f=P_1%20%3D%20100kPa)
![\dot{m} = 5kg/s](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D%205kg%2Fs)
![z_2 = 20m](https://tex.z-dn.net/?f=z_2%20%3D%2020m)
For this problem we know that as pressure, temperature as velocity remains constant, then
![h_1 = h_2](https://tex.z-dn.net/?f=h_1%20%3D%20h_2)
![V_1 = V_2](https://tex.z-dn.net/?f=V_1%20%3D%20V_2)
Then we have that our equation now is,
![\dot{m}(gz_1) = \dot{m}(gz_2)+\dot{W}](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%28gz_1%29%20%3D%20%5Cdot%7Bm%7D%28gz_2%29%2B%5Cdot%7BW%7D)
![\dot{W} = \frac{(5)(9.81)(0-20)}{1000}](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%20%3D%20%5Cfrac%7B%285%29%289.81%29%280-20%29%7D%7B1000%7D)
![\dot{W} = -0.98kW](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%20%3D%20-0.98kW)