Answer:
44.13015
Explanation:
use the 9.8067 newtons to 1 kg conversion
gravity is like a gas that sticks us to ground no matter what object is falling they were both fall down at the same time because it doesn't matter the mass it just matters like the curve around them like if the curve and like their sides
Answer:
2.122 second
Explanation:
T1 = 3 s
L1 = L
L2 = L/2
As we know the time period of a simple pendulum is related by the length of the pendulum as

Here, only the length of pendulum changes and the value of g is constant so,


T2 = 2.122 second
Answer:
The final speed at the gree light is 5.714 m/s
Explanation:
Given that,
Initial speed of the motorist (U) = 20m/s
Displacement of the traffic light (S) = 200m
time taken to slam the brake (t₁) = 1s
Now, the displacement of the motorist, till she slams the brake
S₁ = U × t₁
= 20 × 1
= 20m
The remaining distance would be
S₂ = S - S₁
S₂ = 200 - 20
S₂ = 180m
Now, the deceleration of the motorist
S₂ = Ut + 1/2at²
180 = (20 × 14) + 0.5a(14)²
a = - 1.02m/s²
The final speed would be
v = u + at
v = 20 + (- 1.02)(14)
v = 5.714 m/s
The final speed at the gree light is 5.714 m/s
Answer:
Explanation:
Force on a charged particle placed in an Electric field is given by the product of the magnitude of Electric Field and charge on the particle.
The direction of the force will be given by the nature of a charge on the particle. If the charge is positively charged then the force acting will be in the direction of the Electric field.
If the charge is negatively charged then force acting will be opposite to the direction of the electric field.
Thus no extra information is needed to determine the direction of force.