Number 4 is correct a^0=1 for all real number a
number 5
y^2(y^2=y^(2+2)=y^4 correct
y^6/y^2=y^(6-2)=y^4 correct
y^0=1 false
y^9/y^5=y^(9-5)=y^4 correct
y^4(y^1)=y^(4+1)=y^5 false
'Tis a Binomial. if it were a monomial, there would be no operator between 6x^2 and 2xy^2
Answer:
here's what we know:
a + b = 72
a - b = 26
We can use the elimination method to solve this problem:
a + b = 72
a - b = 26
---------------
2a = 98
Divide both sides by 2:
a = 49
So we now have:
49 + b = 72
and:
49 - b = 26
Subtract 49 from both sides:
b = 23
and
-b = -23 (multiply both sides by -1) → b = 23
Step-by-step explanation:
The answer is C) y=-5/2x-3
