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kherson [118]
3 years ago
7

Help

Engineering
1 answer:
Rama09 [41]3 years ago
3 0

Answer:

er of passes through zero

Example:

Input data:

10

1 3 -2 -6 4 10 1 -5 4 1 Output data:

4

Explanation:

There are 4 sign changes between two consecutive samples:

3 -2 -> sign change (first zero crossing)

-6 4 -> sign change (second zero crossing)

Explanation:

er of passes through zero

Example:

Input data:

10

1 3 -2 -6 4 10 1 -5 4 1 Output data:

4

Explanation:

There are 4 sign changes between two consecutive samples:

3 -2 -> sign change (first zero crossing)

-6 4 -> sign change (second zero crossing)er of passes through zero

Example:

Input data:

10

1 3 -2 -6 4 10 1 -5 4 1 Output data:

4

Explanation:

There are 4 sign changes between two consecutive samples:

3 -2 -> sign change (first zero crossing)

-6 4 -> sign change (second zero crossing)er of passes through zero

Example:

Input data:

10

1 3 -2 -6 4 10 1 -5 4 1 Output data:

4

Explanation:

There are 4 sign changes between two consecutive samples:

3 -2 -> sign change (first zero crossing)

-6 4 -> sign change (second zero crossing)er of passes through zero

Example:

Input data:

10

1 3 -2 -6 4 10 1 -5 4 1 Output data:

4

Explanation:

There are 4 sign changes between two consecutive samples:

3 -2 -> sign change (first zero crossing)

-6 4 -> sign change (second zero crossing)

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After the load impedance has been transformed through the ideal transformer, its impedance is: + . Enter the real part in the fi
frozen [14]

Answer:

Ig =7.2 +j9.599

Explanation: Check the attachment

6 0
3 years ago
A room has a width of 14.1 feet, a length of 15.5 feet, and a ceiling height of 12.0 ft. The average flow rate for this room's a
prohojiy [21]

Answer:

Your question lacks the time required hence i will calculate the Average flow rate using a general concept and an assumed time value of 25 seconds  

ANSWER : 104.904 ft^3/sec

Explanation:

General concept : Average flow rate is the volume of fluid per unit time through an area

Hence the average flow rate of the air conditioning unit of this room

Volume of the room / time taken for the air to cycle the room = v / t

assuming the time taken = 25 seconds

volume of room = width * length * height

                          = 14.1 * 15.5 * 12 = 2622.6 ft^3

Average flow rate = V/ t

                              = 2622.6 / 25  = 104.904 ft^3/sec

8 0
3 years ago
Which phrase best describes a safety-critical system? A. a system that faces a very high risk of failure B. a system isolated fr
KIM [24]

Answer:

B.

Explanation:

A safety-critical system (SCS) or life-critical system is a system whose failure or malfunction may result in one (or more) of the following outcomes: death or serious injury to people. loss or severe damage to equipment/property.

7 0
3 years ago
Concerned with the number of maintenance visits the rocket can undergo before being out of service, you have been informed that
Ainat [17]

Answer:

(a) Mn = M₁ + (n-1) (M₂ -M₁) = 1 + (n- 1) 1 = n (b) n > 10 (exceed 10) or n =11 (c) n >50 or n= 51

After making a journey of 51 times, the rocket will be discarded

Explanation:

Solution

(a) Let Mn denotes the number of  maintenance visits after the nth journey

Then M₁ = 1 , M₂ = 1 +M₁ = 2, M₃ = 1 +M₂ = 3

We therefore, notice that M follows an arithmetic sequence

So,

Mn = M₁ + (n-1) (M₂ -M₁)

= 1 + (n- 1) 1 = n

or Mn =n

(b)  For what value of n we will get  fro Mn > 10

Thus,

n > 10 (exceed 10) or n =11

(c)Similarly of Mn is greater than 50 or Mn>50, the rocket will not be used or reused

So,

n >50 or n= 51

After making a journey of 51 times, the rocket will be discarded

7 0
4 years ago
An electric motor is to be supported by four identical mounts. Each mount can be treated as a linear prevent problems due requir
Artyom0805 [142]

GIVEN:

Amplitude, A = 0.1mm

Force, F =1 N

mass of motor, m = 120 kg

operating speed, N = 720 rpm

\frac{A}{F} =  \frac{0.1\times 10^{-3}}{1} = 0.1\times 10^{-3}

Formula Used:

A = \frac{F}{\sqrt{(K_{t} - m\omega ^{2}) +(\zeta \omega ^{2})}}

Solution:

Let Stiffness be denoted by 'K' for each mounting, then for 4 mountings it is 4K

We know that:

\omega = \frac{2 \pi\times N}{60}

so,

\omega = \frac{2 \pi\times 720}{60} = 75.39 rad/s

Using the given formula:

Damping is negligible, so, \zeta = 0

\frac{A}{F} will give the tranfer function

Therefore,

\frac{A}{F} = \frac{1}{\sqrt{(4K - 120\ ^{2})}}

0.1\times 10^{-3} =  \frac{1}{\sqrt{(4K - 120\ ^{2})}}

Required stiffness coefficient, K = 173009 N/m = 173.01 N/mm

8 0
3 years ago
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