Answer:
a. 0.55
b. 0.68
c. 0.18
Step-by-step explanation:
a. The probability that E2 does not occur is one minus the probability that E2 occurs:
![1-P(E2)= 1- 0.45\\1-P(E2) = 0.55](https://tex.z-dn.net/?f=1-P%28E2%29%3D%201-%200.45%5C%5C1-P%28E2%29%20%3D%200.55)
b. The probability that either E1 or E2 occurs is given by the sum of their individual probabilities minus their joint probability:
![P(E1\ or\ E2) = P(E1)+P(E2)-P(E1, E2)\\P(E1\ or\ E2)=0.37+0.45-0.14\\P(E1\ or\ E2)=0.68](https://tex.z-dn.net/?f=P%28E1%5C%20or%5C%20E2%29%20%3D%20P%28E1%29%2BP%28E2%29-P%28E1%2C%20E2%29%5C%5CP%28E1%5C%20or%5C%20E2%29%3D0.37%2B0.45-0.14%5C%5CP%28E1%5C%20or%5C%20E2%29%3D0.68)
c. The probability that neither E1 nor E2 occurs is one minus the probability of E1 occurring minus the probability of E2 occurring:
![1-P(E1)-P(E2)= 1- 0.37 -0.45\\1-P(E1)-P(E2) = 0.18](https://tex.z-dn.net/?f=1-P%28E1%29-P%28E2%29%3D%201-%200.37%20-0.45%5C%5C1-P%28E1%29-P%28E2%29%20%3D%200.18)
Use desmos:
This is the piece wise graph
A.<span>Yes, because if you start with 103 pencils and you take away 98 pencils you will be left with 5 pencils. The answer should be +5</span>