Question

1.Convert 2.37 moles of Al(NO3)3 to grams.. Single choice.

Answer 1

Answer:

1.   504.8 g Al(NO3)3

2.   14.3 moles O2

Explanation:

1.

g = moles x molar mass = 2.37 x 212.996 = 504.8 g Al(NO3)3

MM Al(NO3)3 = 212.996 g/mol

2.

moles = mass : molar mass = 456.89: 32 = 14.3 moles O2