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goblinko [34]
3 years ago
9

Just a thought

Physics
1 answer:
Olin [163]3 years ago
6 0

Answer:

Explanation:

THE FOURTEEN WEEKS' COURSES

IN

NATURAL SCIENCE,

BY

J. DORMAN STEELE, A.M., PHI.D.

Fourteen Weeks iq Natural Philosophy,

Fourteen Weeks iq Ctlenqistry,

Fourteen Weeks iq Descriptive Astroqonqy,

Fourteel Weeks iq Popular Geology,

Fourteeq Weeks iQ2 Human P1ysiology,

Fourteen Weeks iq Zoology,

Fourteeq Weeks iq Botany,

A Key, containing Answers to the Questions

and Problems in Steele's I4 Weeks' Courses,

4 1ISTORIC4L SERIES,

ON THE PLAN OF STEELE'S 14 WEEKS IN THE SCIENCES.

A Brief History of the Urlited States,

A Brief History of France,

The same publishers also offer the following standard scientific

vworks, being more extended or difficult treatises than those of

Prof. Steele, though still of Academic grade.

Peck's Ganot's Natural Philosophy,

Porter's Principles of Chemistry,

Jarvis' Physiology and Laws of Healtl,

Wood's Botanist and Florist,

Clanlbers' Elenments of Zoology,

lcIqtyre's Astroqomy and tle Globes,

Page's. Elen~ents of Geology,

Entered according to Act of Congress, in the year 1869, by

A. S. BARNES & CO.,

In the Clerk's Office of the District Court of the United States

for the Southern District of New York.

sTERLE'S KEY.

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How do you think scientists figure out what they think the population will be in 2050?
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If a substance has a pH of 10 -11, it is considered a ...
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hope I helped :)

8 0
4 years ago
A hot-air balloon is rising straight up with a speed of 4.6 m/s. a ballast bag is released from rest relative to the balloon at
kherson [118]

The time taken by the ballast bag to reach the ground is 2.18 s

The ballast bag at rest with respect to the balloon has the upward velocity (u) of 4.6 m/s , which is the velocity of the balloon. When it is dropped from the balloon, its motion is similar to an object thrown upwards with an initial velocity <em>u </em>and it falls under the acceleration due to gravity<em> g.</em>

Taking the upward direction as positive and the downward direction as negative, the following equation of motion may be used.

s=ut+\frac{1}{2}at^2

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g=-9.8 m/s^2

Use the values in the equation of motion and write an equation for t.

s=ut+\frac{1}{2} at^2 \\ -13.4=4.6t-\frac{1}{2}(9.8)t^2\\ 4.9t^2-4.6t-13.4=0

Solving the equation for t and taking only the positive value for t,

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3 years ago
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bogdanovich [222]

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3 years ago
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