Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
2200 / 264 = 8.333333-
Round the answer, which is 8.
So, your answer is A. 8%
The total number of packages completed was 41 and with 60 moustraps per package so 41 x 60 = 2460. Of these, 52 traps were from the previous shift and 34 were rejects so 2460-52-34 = 2374 produced + 24 in the last unsealed package = 2374 +24 = 2398.
Answer:
Sales are (increasing/decreasing)…. _____….(purchases, purchases/month, months/purchases, $/purchases, purchases/$, $, months)
D. (January, February, March, April, May, June, July, August, September, October, November, December)
Find the median<br>
23 ,15, 38 ,34 ,22, 2, 21 ,27 ,26 ,14, 32, 30, 19
xxTIMURxx [149]
First put them in ascending numerical order
2, 14, 15, 19, 22, 21, 26, 27, 23, 30, 32, 34, 38
Then start to eliminate numbers by pair (the farthest number from each side) until you get to 1 or two numbers left (in the very middle)
in this case you will be left with 26, which means that the median is 26