Answer : The equilibrium concentration of 
in the solution is, 
Explanation :
The dissociation of acid reaction is:
Initial conc. c 0 0
At eqm. c-x x x
Given:
c = 
The expression of dissociation constant of acid is:
![K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BC_6H_5COO%5E-%5D%7D%7B%5BC_6H_5COOH%5D%7D)
Now put all the given values in this expression, we get:
![6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}](https://tex.z-dn.net/?f=6.3%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7B%28x%29%5Ctimes%20%28x%29%7D%7B%5B%287.0%5Ctimes%2010%5E%7B-2%7D%29-x%5D%7D)
Thus, the equilibrium concentration of in the solution is,
Answer: The compound is called copper (II) bromide or cupric bromide
Explanation:
The balanced equation of for the above reaction is as follows;
2KOH + H₂SO₄ ---> K₂SO₄ + 2H₂O
stoichiometry of KOH to H₂SO₄ is 2:1
the number of KOH moles reacted - 0.124 mol/L x 0.046 L = 0.0057 mol
for complete neutralisation the base should react with acid in 2:1 molar ratio
if 2 mol of KOH reacts with 1 mol of H₂SO₄
then 0.0057 mol of KOH reacts with - 1/2 x 0.0057 mol = 0.0029 mol
the number of H₂SO₄ moles in 28.1 mL - 0.0029 mol
Molarity is number of H₂SO₄ moles in 1 L
therefore number of H₂SO₄ moles in 1 L - 0.0029 mol / 0.0281 L = 0.103 M
molarity of H₂SO₄ is 0.103 mol/L
Answer:
The Florian predict the metamorphic rocks because it changes when subjected to heat and pressure.
Explanation:
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