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Maslowich
3 years ago
13

A 33 kg box sits at rest on a tabletop.

Physics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

323.4N

Explanation:

Given parameters:

Mass of the box = 33kg

Unknown:

Normal force on the body  = ?

Solution:

The normal force of a body is the vertical force the body exerts on another body.

It is expressed as;

        Normal force  = mass x acceleration due to gravity

Acceleration due to gravity  = 9.8m/s²

Normal force  = 33 x 9.8  = 323.4N

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In a popular classroom demonstration, a cotton ball is placed in the bottom of a strong test tube. A plunger fits inside the tub
mario62 [17]

Answer:

An increase in air temperature because of its compression.

Explanation:

The Gay-Lussac's Law states that a gas pressure is directly proportional to its temperature in an enclosed system to constant volume.  

P = kT  

<em>where P: is the gas pressure, T: is the gas temperature and k: is a constant.</em>

Therefore, due to Gay-Lussac's Law, when the plunger is pushed down very rapidly, the pressure of the air increase, which leads to its temperature increase. That is why cotton flashes and burns.      

I hope it helps you!

3 0
3 years ago
A museum curator moves artifacts into place on various different display surfaces. If the curator moves a 145 kg aluminum sculpt
NikAS [45]
We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
8 0
3 years ago
Read 2 more answers
The components of vector A are Ax and Ay (both positive), and the angle that it makes with respect to the positive x axis is θ.
DIA [1.3K]

Answer:

a) \theta = tan^{-1} (\frac{11}{11})= tan^{-1} (1)=45 degrees

b) \theta = tan^{-1} (\frac{11}{19})= tan^{-1} (0.579)=30.07 degrees

c) \theta = tan^{-1} (\frac{19}{11})= 59.93 degrees

Explanation:

If we have a vector A= (A_x ,A_y) in a two dimensional space. The angle respect the x axis can be founded from the following expression:

tan (\theta)= \frac{A_y}{A_x}

And then the angle is given by:

\theta = tan^{-1} (\frac{A_y}{A_x})

Part a

Ax = 11 m and Ay = 11 m

For this case the angle would be:

\theta = tan^{-1} (\frac{11}{11})= tan^{-1} (1)=45 degrees

Part b

Ax = 19 m and Ay = 11 m

For this case the angle would be:

\theta = tan^{-1} (\frac{11}{19})= tan^{-1} (0.579)=30.07 degrees

Part c

Ax = 11 m and Ay = 19 m

For this case the angle would be:

\theta = tan^{-1} (\frac{19}{11})= 59.93 degrees

8 0
3 years ago
Read 2 more answers
Suppose there is a pendulum with length 5m hanging from a ceiling. A ball of mass 2kg is attached is attached to the bottom of t
Dafna1 [17]

Answer:

1.84 m from the initial point (3.16 m from the ceiling)

Explanation:

According to the law of conservation of energy, the initial kinetic energy of the ball will be converted into gravitational potential energy at the point of maximum height.

Therefore, we can write:

\frac{1}{2}mv^2 = mg\Delta h

where

m = 2 kg is the mass of the ball

v = 6 m/s is the initial speed of the ball

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta h is the change in height of the ball

Solving for \Delta h,

\Delta h = \frac{v^2}{2g}=\frac{6^2}{2(9.8)}=1.84 m

So, the ball raises 1.84 compared to its initial height.

Therefore:

- if we take the initial position of the ball as reference point, its maximum height is at 1.84 m

- if we take the ceiling as reference point, the maximum height of the ball will be

5 m - 1.84 m = 3.16 m from the ceiling

7 0
4 years ago
How much power is needed to lift the 200-N object to a height of 10 m in 4 s?
harkovskaia [24]

Answer:

500 watts

Explanation:

Recall that the definition of power is the amount of energy delivered per unit of time.

In our case, the energy delivered is potential energy which we can estimate as the product of the weight of the object times the distance it is lifted above ground:

200 N x 10 m = 2000  Nm

then the power is the quotient of this potential energy divided the time it took to lift the object to that position:

Power = 2000 / 4   Nm/s = 500 Nm/s = 500 watts

6 0
3 years ago
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