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3 years ago

Please help i have an exam next week and im really stuck on this

Mathematics

2 answers:

ruslelena [56]3 years ago

6 0

Answer:

Area = 96 square cm

Step-by-step explanation:

Area of the figure = (2 x Area of triangles) + Area of square

$Area \ of \ triangle = \frac{1}{2} \times base \ height = \frac{1}{2} \times 8\times 4 = 16cm^2\\\\Area \ of \ square = side \times side = 8 \times 8 = 64cm^2$

Therefore, $Area \ of \ the\ figure = (2 \times 16) + 64 = 32 + 64 = 96cm^2$

vaieri [72.5K]3 years ago

3 0

The area is 96 square cm

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A 12 cm by 20 cm painting hangs in a museum. The museum curator wants to hang other paintings in the gallery that are proportion

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Answer:

A. 1.5 cm by 2.5 cm

B. 27 cm by 45 cm

C. 9 cm by 15 cm

D. 30 cm by 50 cm

Step-by-step explanation:

The dimensions of the original painting = 12 cm by 20 cm painting

Hence, the proportion is:

12/20 = 0.6

Hence, we compare the options given in the question.

A. 1.5 cm by 2.5 cm

= 1.5/2.5 = 0.6 , option A is correct

B. 27 cm by 45 cm

27cm/45 cm = 0.6 Option B is correct

C. 9 cm by 15 cm

9cm/15cm = 0.6 , Option C is correct

D. 30 cm by 50 cm

30 cm /50 cm = 0.6 Option D is correct

E. 6 cm by 14 cm

6cm/14 cm = 0.4285714286

Option E is not correct

Therefore, Options A to D are the correct options

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

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Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

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Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

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3 years ago

211 minus 87.4 decimal subtraction

Pavlova-9 [17]

<u>211 - 87.40</u> equals 123.60.

To see if your answer is correct just <u>add 123.60 and 87.40 together</u>.

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4 years ago

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Answer:

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