Question

Can someone help me?!!!!!

Answer 1

Hello!

The answer is:

The third option, the approximate magnitude of the given vector is 9.9 units.

$|A|=9.9units$

Why?

To calculate the magnitude (length) of a vector, we need to apply the following formula:

$|A|=\sqrt{(A_x)^{2} +(A_y)^{2} }$

So, we are given the vector:

$A=(7.6,-6.4)$

Then,  substituting and calculating the magnitude of the vector, we have:

$|A|=\sqrt{(7.6)^{2} +(-6.4)^{2}}=\sqrt{57.76+40.96}=\sqrt{98.72}\\\\|A|=\sqrt{98.72}=9.9units$

Hence, we have that the correct option is the third option, the approximate magnitude of the given vector is 9.9 units.

$|A|=9.9units$

Have a nice day!