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irakobra [83]
3 years ago
7

Can someone help me?!!!!!

Physics
1 answer:
saveliy_v [14]3 years ago
3 0
<h2>Hello!</h2>

The answer is:

The third option, the approximate magnitude of the given vector is 9.9 units.

|A|=9.9units

<h2>Why?</h2>

To calculate the magnitude (length) of a vector, we need to apply the following formula:

|A|=\sqrt{(A_x)^{2} +(A_y)^{2} }

So, we are given the vector:

A=(7.6,-6.4)

Then,  substituting and calculating the magnitude of the vector, we have:

|A|=\sqrt{(7.6)^{2} +(-6.4)^{2}}=\sqrt{57.76+40.96}=\sqrt{98.72}\\\\|A|=\sqrt{98.72}=9.9units

Hence, we have that the correct option is the third option, the approximate magnitude of the given vector is 9.9 units.

|A|=9.9units

Have a nice day!

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