Answer:
Volume of HNO₃ required = 140 mL
Explanation:
Given data:
Molarity of HNO₃ = 0.563 M
mass of BaCO₃ = 7.83 g
Volume of HNO₃ = ?
Solution:
First of all we will write the balance chemical equation
2HNO₃ + BaCO₃ → Ba(NO₃)₂ + H₂O + CO₂
Number of moles of BaCO₃ = mass / molar mass
Number of moles of BaCO₃ = 7.83 g / 197.34 g/mol
Number of moles of BaCO₃ = 0.04 mol
Now we compare the moles of BaCO₃ and HNO₃ .
BaCO₃ : HNO₃
1 : 2
0.04 : 2×0.04 = 0.08 mol
Volume of HNO₃ required = number of moles / Molarity
Volume of HNO₃ required = 0.08 mol / 0.563 mol/L
Volume of HNO₃ required = 0.14 L
0.14 × 1000 = 140 mL
Answer:
polarity is a separation of electric charge leading to a molecule or its chemical groups having an electric dipole moment, with a negatively charged end and a positively charged end.
The difference between all of them in the make-up of the R group.
Answer:
Explanation:
number 12 is magnesium i think which is group lla which is B alkaline earths
0.116 V is the e value for the oxidation of cytochrome c by the cue redox center in complex iv when the ratio of cyst c (fe3 ) /cyst c (fe2 ) is 20 and the ratio of cue (cu2 )/cue (cu ) is 3.
<h3>
Explain the process of oxidation of cytochrome c.</h3>
When cytochrome c is oxidized by mitochondrial cytochrome oxidase (COX), it attaches to Apaf-1 to produce the apoptozole, which activates pro-caspase-9 and causes cell death. Cyst can be created from cytosolic cytochrome c. In the IMS, oxidized cytochrome c can scavenge superoxide without converting it into H2O2, a process that happens naturally but is accelerated by SOD. The benefit of scavenging superoxide independently of H2O2 synthesis is reducing the possibility of hydroxyl radical generation via the Fenton reaction.
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