The acceleration of the runner in the given time is 2.06m/s².
Given the data in the question;
Since the runner begins from rest,
- Initial velocity;
![u = 0](https://tex.z-dn.net/?f=u%20%3D%200)
- Final velocity;
![v = 13.4m/s](https://tex.z-dn.net/?f=v%20%3D%2013.4m%2Fs)
- Time elapsed;
![t = 6.5s](https://tex.z-dn.net/?f=t%20%3D%206.5s)
Acceleration of the runner; ![a = \ ?](https://tex.z-dn.net/?f=a%20%3D%20%5C%20%3F)
<h3>Velocity and Acceleration</h3>
Velocity is the speed at which an object moves in a particular direction.
Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion
![v = u + at](https://tex.z-dn.net/?f=v%20%3D%20u%20%2B%20at)
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
To determine the acceleration of the runner, we substitute our given values into the equation above.
![v = u + at\\\\13.4m/s = 0 + (a * 6.5s)\\\\13.4m/s = a * 6.5s\\\\a = \frac{13.4m/s}{6.5s}\\ \\a = 2.06m/s^2](https://tex.z-dn.net/?f=v%20%3D%20u%20%2B%20at%5C%5C%5C%5C13.4m%2Fs%20%3D%200%20%2B%20%28a%20%2A%206.5s%29%5C%5C%5C%5C13.4m%2Fs%20%3D%20a%20%2A%206.5s%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B13.4m%2Fs%7D%7B6.5s%7D%5C%5C%20%5C%5Ca%20%3D%202.06m%2Fs%5E2)
Therefore, the acceleration of the runner in the given time is 2.06m/s².
Learn more about Equations of Motion: brainly.com/question/18486505