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Arlecino [84]
3 years ago
11

In Environment A, trees are growing back and some of the larger animals are returning to a logged forest. In Environment B, lich

ens and moss are growing on a rocky mountainside that was scraped bare as a glacier retreated. Now, hundreds of years later, some small grasses, shrubs, and animals live there. Which statement best describes both situations? Environment A is undergoing succession, and Environment B is not. Environment A is not undergoing succession, and Environment B is. Both environments are undergoing the same kind of succession. Both environments are undergoing succession, but different kinds.
Chemistry
2 answers:
forsale [732]3 years ago
5 0

Answer the answer is b: environment a is undergoing succession, and environment b is.

Explanation:

i just took the test on ed and got it right

laiz [17]3 years ago
4 0

Answer:

Environment A is not undergoing succession, and Environment B is.

Explanation:

Ecological succession is a gradual process in which ecosystems significantly change over time. Ecological succession is a term used by scientists to describe the change in the structure of a community of different species, or ecosystem. This concept of ecological succession stems from a desire to understand the patterns of change in large and complex ecosystems like forests and how they can exist in places known to be recently formed, such as volcanic islands.

In environment A, the ecosystem is not really changing, organisms are merely returning to their natural habitat. It does not represent any change in the ecosystem.

In environment B, the original ecosystem has become grossly modified, first by the appearance of lichen and mosses and subsequently by grasses shrubs and animals. These sequence of events correlate well with the idea of ecological succession presented in the opening paragraph hence environment B is undergoing ecological succession.

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Determine the equilibrium constant, Keq, at 25°C for the reaction
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Explanation:

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2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

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T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

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