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Kazeer [188]
3 years ago
7

One cup of milk contains 318 mg of calcium. A student drinks 0.318 L of milk in one day. How many mg of calcium does the student

get in one day? (1 cup = 236.6 mL). Express your answer in 3 sig fig and scientific notation.
Chemistry
1 answer:
loris [4]3 years ago
3 0

Answer:

426 mg = 4.26 x 10² mg

Explanation:

1 cup = 237.6 mL x 1 L/1000 mL = 0.2376 L

We divide the liters of milk the student drinks into the volume in liters of a cup to calculate the number of cups the student drinks per day:

number of cups per day = 0.318 L/0.2376 L = 1.34 cup

Now, we multiply the number of cups by the amount of calcium that a cup of milk has:

amount of calcium = 1.34 cup x 318 mg = 426 mg = 4.26 x 10² mg

Therefore, the student gets 426 mg (or 4.26 x 10² mg) of calcium in one day.

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Read 2 more answers
Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N
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Answer:

NH3 is the limiting reactant

The theoretical yield is 216.0 kg urea

The % for this reaction is 78.8 %

Explanation:

<u>Step 1:</u> Data given

Mass of ammonia = 122.5 kg

Mass of carbon dioxide = 211.4 kg

Mass of urea produced = 170.3 kg

Molar mass of ammnoia = 17.031 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Moalr mass of urea = 60.06 g/mol

<u>Step 2:</u> The balanced equation

2NH3(aq) + CO2(aq) --> CH4N2O(aq) + H2O(l)

<u>Step 3:</u> Calculate moles of NH3

Number of moles = mass / Molar mass

Moles NH3 = 122500 grams / 17.031 g/mol

Moles NH3 = 7192.77 moles

<u>Step 4:</u> Calculate moles of CO2

Moles CO2 = 211400 / 44.01 g/mol

Moles CO2 = 4803.45 moles

<u>Step 5</u>: Calculate limiting reactant

For 2 moles NH3 consumed, we need 1 moles of CO2 to produce 1 mole urea and 1 mole H2O

NH3 is the limiting reactant. It will completely be consumed (7192.77 moles).

CO2 is in excess. There will be consumed 7192.77/2 = 3596.4 moles

There will remain 4803.45 - 3596.4 = 1207.05 moles of CO2

<u>Step 6:</u> Calculate moles of urea produced:

For 2 moles NH3 consumed, we need 1 moles of CO2 to produce 1 mole urea and 1 mole H2O

For 7192.77 moles of NH3, we have 3596.4 moles of urea produced

<u>Step 7: </u>Calculate mass of urea

Mass urea = moles urea * molar mass urea

Mass urea = 3596.4 moles * 60.06 g/mol

Mass urea = 216000 grams = 216 kg = theoretical yield

<u>Step 8</u>: Calculate % yield

% yield = (actual yield / theoretical yield)*100%

% yield = (170.3 / 216) *100% = 78.8%

The % for this reaction is 78.8 %

3 0
3 years ago
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