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3 years ago

The electronic configuration of an element is given below.

Chemistry

1 answer:

Svetradugi [14.3K]3 years ago

8 0

Answer:

It is reactive because it has to gain an electron to have a full outermost energy level.

Explanation:

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vodka [1.7K]

I cannot see your question to help you... sorry

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3 years ago

When the electron cloud of a molecule is easily distorted, the molecule has a high _____________.a. polarity b. polarizability c

katovenus [111]

Answer: Option (b) is the correct answer.

Explanation:

Polarity is defined as the development of partial charges on the atoms of a molecule.

Whereas polarizability is defined as the ability or measure of how readily an electron cloud is able to get distorted. More is the polarizability more will be the electron is distorted in nature.

A dipole moment is defined as the measurement of the separation of two opposite electrical charges.

Thus, we can conclude that when the electron cloud of a molecule is easily distorted, the molecule has a high polarizability.

6 0

3 years ago

PLEASE HELP ME ASAP! PLEASE PLEASE PLEASE!

dsp73

It’s C because the oak trees create a population

4 0

3 years ago

Read 2 more answers

One mole of oxygen gas is at a pressure of 6.00 atm and a temperature of 27.0°C. (a) If the gas is heated at constant volume unt

Umnica [9.8K]

Answer: a) 900 K

b) 1200 K

Explanation:

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 6.00 atm

V= Volume of the gas = ?

T= Temperature of the gas = 27°C = 300 K $0^00C=273K$

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas = 1

$V=\frac{nRT}{P}=\frac{1\times 0.0821\times 300}{6.00}=4.10L$

a) To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=6.00atm\\T_1=300K\\P_2=3\times 6.00=18.0atm\\T_2=?$

Putting values in above equation, we get:

$\frac{6.00}{300K}=\frac{18.0}{T_2}\\\\T_2=900K$

The final temperature is 900 K

b) The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 6.00 atm

$P_2$ = final pressure of gas = $2\times 6.00atm=12.0atm$

$V_1$ = initial volume of gas = 4.10 L

$V_2$ = final volume of gas = $2\times 4.10 L=8.20L$

$T_1$ = initial temperature of gas = $300K$

$T_2$ = final temperature of gas =?

Now put all the given values in the above equation, we get:

$\frac{6.00\times 4.10}{300}=\frac{12.0\times 8.20}{T_2}$

$T_2=1200K$

The final temperature is 1200 K

5 0

3 years ago

A 2.5 L container is filled with propane. The ambient temperature is 25°C and the

vlabodo [156]

Answer:

3.3atm is the new pressure of the container

Explanation:

In the car, the temperature of the container increases from 25°C =298K to 55°C = 328K. To solve this question we must use the Boyle's law that state that the pressure of a gas is directly proportional to its absolute temperature under constant volume. The equation is:

P1T2 = P2T1

<em>Where P is pressure and T absolute temperature of 1, initial state of the gas and 2, final state.</em>

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Replacing:

P1 = 3atm

T2 = 328K

P2 = ?

T1 = 298K

3atm*328K = P2*298K

P2 = 3.3atm is the new pressure of the container

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6 0

3 years ago

Read 2 more answers