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blagie [28]
3 years ago
9

Anyone know this question?

Chemistry
1 answer:
RideAnS [48]3 years ago
5 0

Answer:

may be 6

( I am not sure ,just guess haha)

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A) Calculate the pH of a 2.0x10-4 M solution of aniline hydrochoride, C6H5NH3Cl.
igor_vitrenko [27]

Given the concentration of aniline hydrochloride is 2.0 *10^{-4} M

Aniline hydrochloride is the conjugate acid of aniline a weak base.

pH can be calculated from pK_{a} anilinium ion the conjugate acid of aniline.

8 0
3 years ago
Read 2 more answers
One brand of vinegar has a pH of 4.5. Another brand has a pH of 5.0. The equation for the pH of a substance is pH = –log[H+], wh
grigory [225]
[H+] in first brand:
4.5 = -log([H+])
[H+] = 10^(-4.5)

[H+] in second brand:
5 = -log[H+]
[H+] = 10^(-5)

Difference = 10^(-4.5) - 10^(-5)
= 2.2 x 10⁻⁵

The answer is A.
7 0
3 years ago
Read 2 more answers
aspirin C6H4(CO2)(CO2CH3),can be prepared in the chemistry laboratory by the reactions of salicylic acid, C6H4(CO2H)(OH),with ac
Ket [755]
262mol 1=kg
g=1000
from stoichoimetry

x=102*1000/360
x=102000/360
x=283.33

density =m/v
=283.33/1.082
=262mol

8 0
4 years ago
What will be the charge of an atom containing eight protons, nine neutrons, and 10 electrons?
Wittaler [7]
The charge would be -2 because there are 2 more electrons than protons, and electrons have a negative charge.
6 0
3 years ago
What is the emperical formula of a compound containing 40.1% carbon and 6.6% hydrogen​
levacccp [35]

Answer:

CH₂

Explanation:

Given parameters:

Percentage composition:

          Carbon  = 40.1%

          Hydrogen  = 6.6%

Unknown:

Empirical formula of the compound  = ?

Solution:

The empirical formula of a substance is its simplest formula.

 Elements                             Carbon                             Hydrogen

Percentage

Composition                           40.1                                     6.6

Molecular mass                        12                                         1

Number of moles                  40.1/12                                  6.6/1

                                                3.342                                    6.6

Divide through by

the smallest                         3.342/3.342                           6.6/3.342

                                                      1                                        2

So the empirical formula of the compound is CH₂

5 0
3 years ago
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