1 - In what organelle or membrane are triacylglycerols synthesized and fatty acids elongated?
A - Lysosomes
B - Peroxisome
C - Endoplasmic reticulum
D - Ribosomes
E - Nucleus
The answer is Endoplasmic reticulum
Answer:
The correct answer is 0.020 atm.
Explanation:
Partial pressure is calculated by using the formula,
Partial pressure = Mole fraction × Total pressure
The partial pressure of oxygen in a mixture can be calculated by using the formula,
Mole fraction of oxygen in mixture = Number of moles of oxygen / No. of moles of oxygen + No. of moles of Helium
(1 gg or gigagram is equal to 10⁹ grams)
= 2 × 10⁹/32 /2 × 10⁹/32 + 98 × 10⁹ / 4
= 2.54 × 10⁻³
Now the partial pressure of oxygen = Mole fraction of oxygen × Total pressure of oxygen
= 2.54 × 10⁻³ × 8.0 atm
= 0.02032 atm
= 0.020 atm
Answer:
6.9428 kg of CO2
Explanation:
1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.
9.5 x 10^25 CO2 molecules = 157.75 moles CO2
2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.
= 6942.79g
3) Convert 6942.79 grams into kilograms (divide by 1000):
6.9428 kg
Answer:
a. 1.00 x 10⁴ J = 10.0 kJ
b. 1.42 x 10⁴ J = 14.2 kJ
Explanation:
Given the change in temperature during the reaction and assuming the volume of water and density remains constant, the change in enthalpy for the reaction will be given by
ΔHxn = Q = mCΔT where,
m= mass of water
C= specific heat of water, and
ΔT= change in temperature
a. mH₂O = 400.0 mL x 1.00g/mL = 400.00 g
Q = ΔHrxn = 400.00g x 4.184 J/gºC x 6.00 ºC = 1.00 x 10⁴ J = 10.0 kJ
b. mH₂O = 200.0 mL x 1.00 g/mL = 200.0 g
Q = ΔHrxn = 200.00 g x 4.184 J/gºC x 17.0ºC = 1.42 x 10⁴ J = 14.2 kJ