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3 years ago

How does an inclined plane affect the effort needed to move a load vertically?

1 answer:

5 0

If we pull an object vertically upwards then we need to apply a force which is equal in the magnitude of the weight of the object

$F = mg$

now when we pull the same object upwards along an inclined plane with angle then we require a force which will balance the component of weight along the inclined

so it is given as

$F' = mgsin\theta$

so as if we compare the two forces we can say that since the value of sine is always less than 1 for an angle less than 90 degree

so in the 2nd case when we pull the object along the inclined plane it will require less effort

so correct answer is

<em>A. reduce effort</em>

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Water enters a baseboard radiator at 180 °F and at a flow rate of 2.0 gpm. Assuming the radiator releases heat into the room at

beks73 [17]

Answer:

Temperature of water leaving the radiator = 160°F

Explanation:

Heat released = (ṁcΔT)

Heat released = 20000 btu/hr = 5861.42 W

ṁ = mass flowrate = density × volumetric flow rate

Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³

ṁ = 1000 × 0.000126 = 0.126 kg/s

c = specific heat capacity for water = 4200 J/kg.K

H = ṁcΔT = 5861.42

ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C

And in change in temperature terms,

10°C= 18°F

11.08°C = 11.08 × 18/10 = 20°F

ΔT = T₁ - T₂

20 = 180 - T₂

T₂ = 160°F

8 0

3 years ago

What would be the daughter product of the beta decay of lead-212 and what would be the daughter product of the alpha decay of po

kati45 [8]

Answer:

lead with Z = 82 is transformed into Bismuth with Z = 73

The Po with Z = 84 becomes Pb with Z = 82

Explanation:

Beta decay occurs when a neutron emits an electron and an anti neutrino from the atomic nucleus, therefore the atomic number of the material increases by one unit.

Pb + e + ν → Bi

lead with Z = 82 is transformed into Bismuth with Z = 73

In alpha decay, a helium nucleus is emitted from the nucleus of the atom, therefore the atomic number decreases by two units.

Po +α → Pb

The Po with Z = 84 becomes Pb with Z = 82

4 0

3 years ago

Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then

Mnenie [13.5K]

Answer:

∧·······∵·······∴·······Hello :D········∴·······∵·······∧

How is Mass or volume change affect density?: Density is an intensive property of the material or substance and depends upon the relationship between the mass and volume. Unless the mass changes in relation to the volume, the density will not change.

Are mass and volume related?: Mass and volume are two units used to measure objects. Mass is the amount of matter an object contains, while volume is how much space it takes up.We can say that the volume of the object is directly proportional to its mass. As the volume increases the mass of the object increases in direct proportion.

How can density of an object be determined?: If the mass of an object increases then its density increases because density is directly proportional to mass.

Hope this helped too. ~(;-;)~

Explanation:

<h2>Hope this helps! </h2><h2 />

8 0

3 years ago

How does cell transport make cellular respiration and photosynthesis work?

Aloiza [94]

Answer:

okjjjjkkkkjjjjhhjjikhggbvvh

4 0

3 years ago

Is mass is 88.2 and height of distance is 25m, how do you find speed?

Natasha_Volkova [10]

Answer:

The velocity will be v = 22.1[m/s]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy is converted to kinetic energy. For this problem we will take the point with maximum potential energy when the body is 25 [m] high. By the time the height is zero, the potential energy will have been transformed into kinetic energy, and we can find the velocity of the body.

$Ep = m*g*h\\where:\\m = mass = 88.2[kg]\\h = elevation = 25[m]\\g = gravity = 9.81 [m/s^2]\\Ep = 88.2*25*9.81 = 21631.05[J]\\$

Now we know that the energy will be transformed.

$Ek=Ep\\Ek=0.5*m*v^{2} \\where:\\v=velocity [m/s]\\v=\sqrt{\frac{Ek}{0.5*m} } \\v=\sqrt{\frac{21631.05}{0.5*88.2} } \\v=22.14[m/s]$

4 0

3 years ago