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3 years ago

How does an inclined plane affect the effort needed to move a load vertically?

1 answer:

5 0

If we pull an object vertically upwards then we need to apply a force which is equal in the magnitude of the weight of the object

$F = mg$

now when we pull the same object upwards along an inclined plane with angle then we require a force which will balance the component of weight along the inclined

so it is given as

$F' = mgsin\theta$

so as if we compare the two forces we can say that since the value of sine is always less than 1 for an angle less than 90 degree

so in the 2nd case when we pull the object along the inclined plane it will require less effort

so correct answer is

<em>A. reduce effort</em>

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What will happen to the force felt between two charged objects if the distance between them is 1/3rd of the original distance

kenny6666 [7]

Answer:

New force = 9(initial force)

Explanation:

The force between two charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

Where

d is the original distance

Let d' is the new distance such that, r' = r/3

New force,

$F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{3})^2}\\\\F'=9\times \dfrac{kq_1q_2}{r^2}\\\\F'=9F$

So, the new force becomes 9 times the initial force.

4 0

3 years ago

What is the specific heat of the masses in this experiment? Infer the substance the masses are made of and explain your inferenc

Liono4ka [1.6K]

The metal whose specific heat capacity is close to the obtained value is aluminum.

<h3>What is specific heat capacity</h3>

The specific heat capacity of an object is the heat required to raise a unit mass of the substance by 1 kelvin.

$Q= mc\Delta \theta$

where;

c is the specific heat capacity
Δθ is change in temperature

Let the mass of the water = 50 g

mass of the metal for this first trial = 50 g

The heat gained by the water is calculated as follows

$Q = 50 \times 4.184 \times 8.4\\\\Q = 1757.28 \ J$

Specific heat capacity of the metal for the first trial is calculated as follows;

Heat gained by water = Heat lost by metal

$C = \frac{Q}{m\Delta T} = \frac{1757.28}{50\times 8.4} = 4.184 \ J/g^oC$

Specific heat capacity of the metal for the second trial;

mass of metal = 200 - mass of water = 150 g

$C_2 = \frac{1757.28}{150 \times 15.2} = 0.77 \ J/g^oC$

Specific heat capacity of the metal for the third trial;

$C_3 = \frac{1757.28}{250 \times 20.8} = 0.34\ J/g^oC$

Specific heat capacity of the metal for the fourth trial;

$C_4 = \frac{1757.28}{350 \times 25.4} = 0.19\ J/g^oC$

Specific heat capacity of the metal for the fifth trial;

$C_5 = \frac{1757.28}{450 \times 29.6} = 0.13\ J/g^oC$

Average specific heat capacity

$C = \frac{4.184 + 0.77 + 0.34+ 0.19 + 0.13 }{5} = 1.12 \ J/g^oC = 1120 J/kg^oC$

The metal whose specific heat capacity is close to the above value is aluminum.

Learn more about specific heat capacity here: brainly.com/question/16559442

8 0

2 years ago

When light goes from one material into another material having a HIGHER index of refractionA) its speed decreases but its wavele

Mnenie [13.5K]

Answer:

E) its speed and wavelength decrease, but its frequency stays the same

Explanation:

First of all, the frequency of a light wave does not depend on the medium, while wavelength and speed do. Therefore, the frequency remains costant.

In particular, the speed of light in a medium is given by:

$v=\frac{c}{n}$

where c is the speed of light in a vacuum and n is the index of refraction. From the formula, we see that v and n are inversely proportional: so, when the light moves into a material with higher index of refraction, its speed decreases.

Moreover, speed is related to wavelength by

$v=\lambda f$

where $\lambda$ is the wavelength and f is the frequency. Since the two quantities are directly proportional, this means that since the speed decreases, the wavelength decreases as well.