What is the last step to take in order to keep food safe?
2 answers:
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Answer:
the engine cool to 40 at 14.07 minutes
Explanation:
Given information
T(5) = 70
= 100
C = 15
Newton's law of cooling :
T(t) = C + ( - C)
where
T(t) = temperature at any given time
C = surrounding temperature
= initial temperature of heated object
k = cooling constant
to find the the time when the engine will be cooled down to 40, we first need to find the cooling constant, k
when t = 5, T(5) = 70
so,
T(t) = C + ( - C)
T(5) = 15 + (100 - 15)
70 = 15 + (85)
= (70 - 15) / 85
-5k = ln (55/85)
k = - ln (55/85) / 5
k = 0.087
thus, we have the eqaution
T(t) = 15 + (85)
now we can determine the time when T(t) = 40
40 = 15 + (85)
= (40-15)/85
-0.0087t = ln (25/85)
t = - ln (25/85)/0.087
t = 14.07 minutes
To solve this problem we will apply the concepts related to the kinematic equations of linear motion. For such an effect we will define the average speed, as the distance traveled in the established time.
Our values are given under the following conditions:
The final distance covered in those 10 seconds at would be
Therefore the average speed would be the sum of those distances in the total travel time
Therefore the average velocity is 30.5m/s