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ch4aika [34]
3 years ago
11

What's autonization of water​

Chemistry
1 answer:
GarryVolchara [31]3 years ago
7 0

Explanation:

The self-ionization of water (also autoionization of water, and autodissociation of water) is an ionization reaction in pure water or in an aqueous solution, in which a water molecule, H2O, deprotonates (loses the nucleus of one of its hydrogen atoms) to become a hydroxide ion, OH−. The hydrogen nucleus, H+, immediately protonates another water molecule to form hydronium, H3O+. It is an example of autoprotolysis, and exemplifies the amphoteric nature of water

Animation of the self-ionization of water

Chemically pure water has an electrical conductivity of 0.055 μS/cm. According to the theories of Svante Arrhenius, this must be due to the presence of ions. The ions are produced by the water self-ionization reaction, which applies to pure water and any aqueous solution:

H2O + H2O ⇌ H3O+ + OH−

Expressed with chemical activities a, instead of concentrations, the thermodynamic equilibrium constant for the water ionization reaction is:

{\displaystyle K_{\rm {eq}}={\frac {a_{\rm {H_{3}O^{+}}}\cdot a_{\rm {OH^{-}}}}{a_{\rm {H_{2}O}}^{2}}}}

which is numerically equal to the more traditional thermodynamic equilibrium constant written as:

{\displaystyle K_{\rm {eq}}={\frac {a_{\rm {H^{+}}}\cdot a_{\rm {OH^{-}}}}{a_{\rm {H_{2}O}}}}}

under the assumption that the sum of the chemical potentials of H+ and H3O+ is formally equal to twice the chemical potential of H2O at the same temperature and pressure.[1]

Because most acid–base solutions are typically very dilute, the activity of water is generally approximated as being equal to unity, which allows the ionic product of water to be expressed as:[2]

{\displaystyle K_{\rm {eq}}\approx a_{\rm {H_{3}O^{+}}}\cdot a_{\rm {OH^{-}}}}

In dilute aqueous solutions, the activities of solutes (dissolved species such as ions) are approximately equal to their concentrations. Thus, the ionization constant, dissociation constant, self-ionization constant, water ion-product constant or ionic product of water, symbolized by Kw, may be given by:

{\displaystyle K_{\rm {w}}=[{\rm {H_{3}O^{+}}}][{\rm {OH^{-}}}]}

where [H3O+] is the molarity (≈ molar concentration)[3] of hydrogen or hydronium ion, and [OH−] is the concentration of hydroxide ion. When the equilibrium constant is written as a product of concentrations (as opposed to activities) it is necessary to make corrections to the value of {\displaystyle K_{\rm {w}}} depending on ionic strength and other factors (see below).[4]

At 25 °C and zero ionic strength, Kw is equal to 1.0×10−14. Note that as with all equilibrium constants, the result is dimensionless because the concentration is in fact a concentration relative to the standard state, which for H+ and OH− are both defined to be 1 molal (or nearly 1 molar). For many practical purposes, the molal (mol solute/kg water) and molar (mol solute/L solution) concentrations can be considered as nearly equal at ambient temperature and pressure if the solution density remains close to one (i.e., sufficiently diluted solutions and negligible effect of temperature changes). The main advantage of the molal concentration unit (mol/kg water) is to result in stable and robust concentration values which are independent of the solution density and volume changes (density depending on the water salinity (ionic strength), temperature and pressure); therefore, molality is the preferred unit used in thermodynamic calculations or in precise or less-usual conditions, e.g., for seawater with a density significantly different from that of pure water,[3] or at elevated temperatures, like those prevailing in thermal power plants.

We can also define pKw {\displaystyle \equiv } −log10 Kw (which is approximately 14 at 25 °C). This is analogous to the notations pH and pKa for an acid dissociation constant, where the symbol p denotes a cologarithm. The logarithmic form of the equilibrium constant equation is pKw = pH + pOH.

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ra1l [238]

Answer:

b. . the element symbol

6 0
3 years ago
Read 2 more answers
13 points for this, you have to show how you did it because i need to figuer out how you did it.
andrey2020 [161]
CO + 2 H2 → CH3OH 
<span> find # of mols in each reactants, </span>

<span>152500 g CO x 1 mol CO / 28.01g CO = 5444 mol CO </span>

<span>24500 g H2 x 1 mol H2 / 2.02 g H2 = 12129 mol H2 </span>

<span>mol ratio between CO and H2 is 1:2, which means each mol of production of CH3OH need 1 mol of CO and 2 mol of H. </span>

<span>H2 is enough to produce 6064 mols of CH3OH but there are only 5444mol of CO. </span>

<span>5444 mol CH3OH x molar mass of CH3OH / 1 mol CH3OH </span>

<span>= 174371 g = 174.4 kg</span>
4 0
3 years ago
3. A balloon is filled with a mystery fluid that has a mass of 1000 kg and a volume of
vaieri [72.5K]
Fluid Density= 1000000g/ 500 mL
10000g/5 mL, 2000 g/mL

Density water= 1 g/mL

It is denser than water so it should sink
3 0
3 years ago
How much heat is needed to raise the temperature of 100g of an iron from 25°C to
Black_prince [1.1K]

Answer:

382.5J

Explanation:

<em>Use the formula:</em>

E = mcΔθ or Q = mcΔT

m = 100g

c = 0.45 J/g°C

ΔT or Δθ = 110 - 25 = 85°

<em>Sub in the values:</em>

E = 100 × 0.45 × 85

= 382.5J

5 0
3 years ago
20 mL hcl HCL density of 1.18 g/mL how many grams of hcl
Reika [66]

Answer: 23.6 grams HCl

Explanation:

The density 1.18g/mL just means that there is 1.18 grams of HCl per 1 mL of it.

So if you have 20 mL of it, it would just be 1.18 * 20 grams. This equals 23.6 grams of HCl.

It's just like if at your supermarket they sold apples for $1.00/lb. If you wanted 5 lbs, it would cost $5.00 ($1.00 * 5).

3 0
4 years ago
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