Heat is transferred at a rate of 2 kW from a hot reservoir at 800 K to a cold reservoir at 300 K. Calculate the rate at which th
e entropy of the two reservoirs changes. (Round the final answer to six decimal places.) The rate at which the entropy of the two reservoirs changes is kW/K.
1 answer:
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Answer:
e= 50 J/kg
Explanation:
Given that
Speed ,v= 10 m/s
Diameter of the turbine = 90 m
Density of the air ,ρ = 1.25 kg/m³
We know that mechanical energy given as
That is why mechanical energy per unit mass will be
Now by putting the values in the above equation we get
e= 50 J/kg
That why the mechanical energy unit mass will be 50 J/kg.