Answer:
The average atomic weight = 121.7598 amu
Explanation:
The average atomic weight of natural occurring antimony can be calculated as follows :
To calculate the average atomic mass the percentage abundance must be converted to decimal.
121 Sb has a percentage abundance of 57.21%, the decimal format will be
57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .
123 Sb has a percentage abundance of 42.79%, the decimal format will be
42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .
Next step is multiplying the fractional abundance to it masses
121 Sb = 0.5721 × 120.904 = 69.169178400
123 Sb = 0.4279 × 122.904 = 52.590621600
The final step is adding the value to get the average atomic weight.
69.169178400 + 52.590621600 = 121.7598 amu
Answer:
C.) perpendicular
Explanation:
A particle with an electric charge experiences the maximum deflecting force when it is positioned perpendicular to the magnetic field.
A substance that cannot be broken down into even by chemical means is called an element. About 90 elements on the Periodic Table can be found naturally on Earth. Three of the most common ones are aluminium, silicon and oxygen.
Sorry I couldn't give you a more specific answer as your question wasn't multiple choice.
Answer:ur needed to gorw up
Explanation:seroiuslsitlty
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Answer:
0.92 g
Explanation:
Given data:
Percentage of NaCl = 1.6%
Amount of NaCl present in 57.2 g = ?
Solution:
1.6% of 57.2 g NaCl:
1.6/100× 57.2 g
0.92 g
So in 57.2 g 1.6% of NaCl is 0.92 g.
