Answer:
n = 1.24 moles
Explanation:
Given that,
Mass = 153 grams
Molar mass of KClO₃ = 122.55 g/mol
We need to find the number of moles.
We know that,
No. of moles = given mass/molar mass
So,
So, there are 1.24 moles in 153 g of KClO₃.
Answer:
The chemical term in the equation for the precipitate of AgCl(s) is n=3.54*10^-3
Explanation:
the quantity of AgCl(s) in moles is:
n = 0.508g / 143.32 g/mol = 3.54*10^-3 mol
to verify it the mass of AgNO3 involved in the reaction should be
n AgNO3 required = n = 3.54*10^-3 mol
the mass of n involved should be higher than n AgNO3
n existing = V*N = 0.523 mol/L * 35*10^-3 L = 18.305*10^-3 mol
Answer:
oxygen, carbon, hydrogen, nitrogen, calcium, and phosphorus.
Explanation:
the mass of the human body is made up of six elements: oxygen, carbon, hydrogen, nitrogen, calcium, and phosphorus.
