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3 years ago

How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?

Chemistry

1 answer:

valkas [14]3 years ago

8 0

Answer:

106.25 mL

Explanation:

For this, we can use

C1×V1=C2×V2

C1 = 0.45

V1 = 85

C2= 0.20

V2= ?

0.45 × 85 = 0.20 × V2

V2= (0.45 × 85)/0.20

V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 =106.25mL

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