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finlep [7]
3 years ago
8

Charlie and Susan are planning a part for 10 people. Charlie finds a location that charges a initial fee of $20 plus $25 per per

son. Susan finds a location whose rental fee is represented by the equation y=15x+100, where x is the number of people in attendance and y is the total cost. Select all the statements that are true. A. Charlie's location is a cheaper location B. Susan's location is cheaper for 10 people. C. The charge for each additional person is greater for Susan's location. D. The charge for each additional person is greater for Charlie's location. E. If the number of people at the party changes to 12, the total cost at each location is the same. There are TWO answers
Please help my promotion is coming No links I just need the answers​
Mathematics
1 answer:
Contact [7]3 years ago
3 0

Answer:

B. Susan's location is cheaper for 10 people.

D. The charge for each additional person is greater for Charlie's location.

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5.2.14. For the negative binomial pdf p (k; p, r) = k+r−1 (1 − p)kpr, find the maximum likelihood k estimator for p if r is know
Volgvan

Answer:

\hat p = \frac{r}{\bar x +r}

Step-by-step explanation:

A negative binomial random variable "is the number X of repeated trials to produce r successes in a negative binomial experiment. The probability distribution of a negative binomial random variable is called a negative binomial distribution, this distribution is known as the Pascal distribution".

And the probability mass function is given by:

P(X=x) = (x+r-1 C k)p^r (1-p)^{x}

Where r represent the number successes after the k failures and p is the probability of a success on any given trial.

Solution to the problem

For this case the likehoof function is given by:

L(\theta , x_i) = \prod_{i=1}^n f(\theta ,x_i)

If we replace the mass function we got:

L(p, x_i) = \prod_{i=1}^n (x_i +r-1 C k) p^r (1-p)^{x_i}

When we take the derivate of the likehood function we got:

l(p,x_i) = \sum_{i=1}^n [log (x_i +r-1 C k) + r log(p) + x_i log(1-p)]

And in order to estimate the likehood estimator for p we need to take the derivate from the last expression and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\frac{x_i}{1-p}

And we can separete the sum and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}

Now we need to find the critical point setting equal to zero this derivate and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}=0

\sum_{i=1}^n \frac{r}{p} =\sum_{i=1}^n \frac{x_i}{1-p}

For the left and right part of the expression we just have this using the properties for a sum and taking in count that p is a fixed value:

\frac{nr}{p}= \frac{\sum_{i=1}^n x_i}{1-p}

Now we need to solve the value of \hat p from the last equation like this:

nr(1-p) = p \sum_{i=1}^n x_i

nr -nrp =p \sum_{i=1}^n x_i

p \sum_{i=1}^n x_i +nrp = nr

p[\sum_{i=1}^n x_i +nr]= nr

And if we solve for \hat p we got:

\hat p = \frac{nr}{\sum_{i=1}^n x_i +nr}

And if we divide numerator and denominator by n we got:

\hat p = \frac{r}{\bar x +r}

Since \bar x = \frac{\sum_{i=1}^n x_i}{n}

4 0
3 years ago
The sum of 3 odd consecutive integers are 93. find the 3 integers
Solnce55 [7]
Let, Your Integers = x, x+2, x+4
Now, x + x+2 + x+4 = 93
3x + 6 = 93
3x = 93 - 6
x = 87/3
x = 29
Then, x+2 = 31, & x+4 = 33

In short, Your Integers would be 29, 31, 33

Hope this helps!
4 0
3 years ago
Plzzzzz help me!!!!!
Darina [25.2K]

Answer: 17.50 give brainliest if it helps

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What’s the best answer?
kow [346]
I think the last one

5 0
3 years ago
A tire company finds that the lifespan for one brand of its tires is normally distributed with a mean of 47,500 miles and a stan
Illusion [34]

Answer:

42580 miles

Step-by-step explanation:

Mean = \mu = 47500

\sigma = 3000

The manufacturer does not want to replace more than 5% of the tires

P(X\leq x)=5\%

P(\frac{x-\mu}{\sigma}\leq \frac{x-47500}{3000})=0.05

By using normal table values :

\frac{x-47500}{3000}=-1.64

x=(-1.64 \times 3000)+47500

x=42580

Hence the approximate number of miles for the warranty is 42580 miles

6 0
3 years ago
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