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Travka [436]
2 years ago
14

If a train is traveling eastward with a constant velocity of 15 m/s, what is the net external force action on it? There is not e

nough information, so it cannot be solved. There is no net force acting on the train. the force from the engines
Physics
2 answers:
sammy [17]2 years ago
6 0

Answer:

There is no net force acting on the train.

Explanation:

The net force equals mass times acceleration:

∑F = ma

The train moves at constant velocity, so its acceleration is 0.  Therefore, the net force is 0.

ExtremeBDS [4]2 years ago
3 0

If a train is travelling eastward with a constant velocity of 15 m/s, there is no net force acting on the train.

Answer: Option B

<u>Explanation: </u>

According to Newton 2nd law, the external force is proportionate to the rates of change of momentum which states that force will be indirectly proportional to the rates of variation in velocity. So, as the velocity is constant for the train, the rate of variation in velocity or the acceleration will be zero. Thus the total external forces acting on the train will be zero. But the train will be moving continuously due to the energy obtained from the engine.

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Each plate of an air-filled parallel-plate capacitor has an area of 45.0 cm2, and the separation of the plates is 0.080 mm. A ba
maw [93]

Answer:

Option (e)

Explanation:

A = 45 cm^2 = 0.0045 m^2, d = 0.080 mm = 0.080 x 10^-3 m,

Energy density = 100 J/m

Let Q be the charge on the plates.

Energy density = 1/2 x ε0 x E^2

100 = 0.5 x 8.854 x 10^-12 x E^2

E = 4.75 x 10^6 V/m

V = E x d

V = 4.75 x 10^6 x 0.080 x 10^-3 = 380.22 V

C = ε0 A / d

C = 8.854 x 10^-12 x 45 x 10^-4 / (0.080 x 10^-3) = 4.98 x 10^-10 F

Q = C x V = 4.98 x 10^-10 x 380.22 = 1.9 x 10^-7 C

Q =  190 nC

3 0
3 years ago
A string under a tension of 68 N is used to whirl a rock in a horizontal circle of radius 3.7 m at a speed of 16.53 m/s. The str
alekssr [168]

Answer:

F = 5253.7 N

Explanation:

As we know that tension force in the string will be equal to the centripetal force on the string

so we will have

T = \frac{mv^2}{L}

now we have

68 = \frac{m(16.53^2)}{3.7}

now we have

68 = 73.8 m

m = 0.92 kg

now when string length is 0.896 m and its speed is 71.5 m/s then we will have

F = \frac{mv^2}{r}

F = \frac{0.92(71.5^2)}{0.896}

F = 5253.7 N

8 0
3 years ago
Read 2 more answers
A 2000 kg car experiences a braking force of 10000N and skids to a 14 m stop. What was the speed of the car just before the brak
Fudgin [204]

Answer:

V = 11.83 m/s

Explanation:

Given the following data;

Mass = 2000 kg

Force = 10000N

Distance = 14 m

To find the final velocity of the car;

First of all, we would determine the acceleration of the car;

Acceleration = force/mass

Acceleration = 10000/2000

Acceleration = 5 m/s²

Next, we would use the third equation of motion to find the final velocity;

V^{2} = U^{2} + 2aS

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

S represents the displacement measured in meters.

Substituting into the equation, we have;

V² = 0² + 2*5*14

V² = 0 + 140

V = √140

V = 11.83 m/s

5 0
2 years ago
To raise an arm upward, the muscle on one side of it contracts. What happens to the muscle on the opposite side of the arm?
enyata [817]

Answer:

It relaxes

Explanation:

I took the test I hope it helps

5 0
3 years ago
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Which of the following substances could be heated from 20°C to 100°C most quickly? Assume identical heat sources are used on all
Lera25 [3.4K]
Hello There!

Your answer is Gold because it has the lowest SH

Hope This Helps You!
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3 0
2 years ago
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