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8_murik_8 [283]
3 years ago
10

HELP ITS DUE BEFORE 11:20

Physics
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

have you searced it

Explanation:

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Which activity directly converts energy from the sun?.
Artist 52 [7]
Photovoltaic cells are well known for their ability to convert solar energy (1) into electrical energy.
3 0
3 years ago
A 120-g block of copper is taken from a kiln and quickly placed into a beaker of negligible heat capacity containing 300 g of wa
gavmur [86]

Answer : The correct option is, (d) 535^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of copper = 0.10cal/g^oC

c_2 = specific heat of water = 1.00cal/g^oC

m_1 = mass of copper = 120 g

m_2 = mass of water = 300 g

T_f = final temperature of mixture = 35^oC

T_1 = initial temperature of copper = ?

T_2 = initial temperature of water = 15^oC  

Now put all the given values in the above formula, we get:

120g\times 0.10cal/g^oC\times (35-T_1)^oC=-300g\times 1.00cal/g^oC\times (35-15)^oC

T_1=535^oC

Therefore, the temperature of the kiln was, 535^oC

7 0
4 years ago
Read 2 more answers
Can we call centre of gravity centre of weight? ​
algol [13]

Answer:

Centre of gravity is a theoretical point in the body where the total weight of the body is thought to be concentrated. In a uniform gravitational field, the centre of gravity is identical to the centre of mass. Yet, the two points do not always coincide.

3 0
3 years ago
An object moves with constant acceleration 3.45 m/s2 and over a time interval reaches a final velocity of 14.0 m/s.
Sav [38]
Assuming the object was originally at rest, it must have been traveling for
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4 0
3 years ago
A person exerts a horizontal force of 190 n in the test apparatus shown in the figure. Find the horizontal force that his flexor
DochEvi [55]

Answer:

Check explanation.

Explanation:

From the question, we know that The person exerted 190N, force on the flexor is unknown. Since, we don't have access to our diagram, we have to make one or two assumption; (1) that ba= 0.3 m, ac= 0.05.

Therefore, the horizontal force that his flexor muscle exerts on his forearm,F(flexor) = (190N) × (0.3m) / 0.05m.

The horizontal force that his flexor muscle exerts on his forearm,F(flexor) = 57 Nm/ 0.05 m.

The horizontal force that his flexor muscle exerts on his forearm,F(flexor) = 1140N.

5 0
3 years ago
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