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s344n2d4d5 [400]
3 years ago
8

Consider a blackbody that radiates with an intensity I1I1I_1 at a room temperature of 300K300K. At what intensity I2I2I_2 will t

his blackbody radiate when it is at a temperature of 400K400K
Physics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

Explanation:

We shall apply Stefan's formula

E = AσT⁴

When T = 300

I₁ = Aσ x 300⁴

When T = 400K

I₂ = Aσ x 400⁴

I₂ / I₁ = 400⁴ / 300⁴

= 256 / 81

= 3.16

I₂ = 3.16 I₁ .

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Answer:

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Explanation:

The total energy of the pendulum is equal to:

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For small oscillations, the equation can be re-arranged into the following form:

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If the amplitude of pendulum oscillations is increase by a factor of 4, the angle of oscillation is 4\theta and the total energy of the pendulum is:

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3 years ago
In the following diagram, the voltage is 1.5 volts and the resistance is 0.35 ohms. Use Ohm's Law to determine the current in th
Angelina_Jolie [31]

Answer:

I = 4.28 [amp]

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The energy transfer in terms of work has the equation:

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