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s344n2d4d5 [400]
3 years ago
8

Consider a blackbody that radiates with an intensity I1I1I_1 at a room temperature of 300K300K. At what intensity I2I2I_2 will t

his blackbody radiate when it is at a temperature of 400K400K
Physics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

Explanation:

We shall apply Stefan's formula

E = AσT⁴

When T = 300

I₁ = Aσ x 300⁴

When T = 400K

I₂ = Aσ x 400⁴

I₂ / I₁ = 400⁴ / 300⁴

= 256 / 81

= 3.16

I₂ = 3.16 I₁ .

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Answer:

t=6.96s

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7 0
3 years ago
A small plastic bead has been charged to -15nC.
marishachu [46]

Answer:

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a = (2.67 x 10^-13) / (1.67 x 10^-27)

a = 1.6 x 10^14 m/s²

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electric field on proton, E = Kq/d²

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a = (2.67 x 10^-13) / (9.1 x 10^-31)

a = 3 x 10^17 m/s²

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Answer:

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