Answer:
4.52×10⁻¹⁰ C
Explanation:
The charge stored in a capacitor is given as,
Q = CV.................... Equation 1
Where Q = Charge stored in a capacitor, C = Capacitance of the capacitor, V = Voltage.
But,
C = e₀A/d.............. Equation 2
Where e₀= permitivity of free space, A = Area of the plates, d = distance of separation of the plates
Substitute equation 2 into equation 1
Q = e₀AV/d................ Equation 3
Given: A = 28.1 cm² = 0.00281 m², V = 69.0 V, d = 3.8 mm = 0.0038 m
Constant: e₀ = 8.85×10⁻¹² F/m.
Substitute into equation 3
Q =8.85×10⁻¹²×0.00281×69/0.0038
Q = 4.52×10⁻¹⁰ C.
Hence the charge on the capacitor = 4.52×10⁻¹⁰ C
