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Dmitry [639]
3 years ago
11

A timing light checks the ignition timing in relation to the ____ position.

Engineering
1 answer:
kogti [31]3 years ago
8 0

Answer:

The timing light is connected to the ignition circuit and used to illuminate the timing marks on the engine's crankshaft pulley or flywheel, with the engine running. The apparent position of the marks, frozen by the stroboscopic effect, indicates the current timing of the spark in relation to piston position.

Explanation:

:)

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A water tank filled with solar-heated water at 40°C is to be used for showers in a field using gravity-driven flow.
Alenkasestr [34]

Answer:

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Explanation:

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Which option demonstrates when most vehicles lose their efficiency?
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Essence of check line in chain surveying
zimovet [89]

Answer:

Following are the description on the chain surveying:

Explanation:

The checking which is also called a beginning of the test is indeed a line uniting the summit of a triangular with other fixed locations from both sides of a triangle. To verify the overall precision of a framework, the check-line is measured. When assessed mostly on the ground, every length of an examination line should match its height. It also is called a proof line that connects the top of the triangle with any fixed location in the contrary direction. It is utilized for verifying the preciseness of a work.

6 0
3 years ago
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Gennadij [26K]

Answer:

II

Explanation:

3 0
3 years ago
The convection coefficient for flow over a solid sphere may be determined by submerging the sphere, which is initially at 25 °C,
sashaice [31]

Answer:

t = 59.37 s

Explanation:

Given data:

thermal diffusivity = \alpha = \frac{k}{\rho c_p} =0.40\times 10^{-0.5}

theraml conductivity = k = 22 W/m.K

h = 300 W/ m^2.K

T_i = 25 degree C = 298 k

T_o = 60 degree C = 333 k

T_{\infty}= 75 degree C =  348 L

diameter d = 0.1 m

characteristics length Lc = r/3 = = 0.0166

Bi = \frac{hLc}{K} = \frac{300\times 0.0166}{22} = 0.226

\tau = \frac{\alpha t}{lc^2} = \frac{0.4\times 10^{-5}\times t}{0.0166^2}

\tau = 0.036 t

\frac{T_o -T_{\infty}}{T_i -T_{\infty}} = Ae^[\lambda^2 \tau}

at Bi = 0.226

Ai = 0.982

\lambda = 0.876

\frac{333348}{298-348} = 0.982e^{-0.879^2 0.036t}

0.3 = 0.982 e^{-0.2t}

0.305 = e^{-0.2t}

-1.187 = - 0.02t

t = 59.37 s

7 0
3 years ago
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