The prefix milli means thousand so the correct conversion factor is 1000mg/g
So, you need to have same ammount of atoms on the left and on the right side of the equation. You need to count the ammount of attoms of every substance on the left, and make sure that on the right side the ammount is same. For example in the 1st one it’s 6Sn+2P4=2Sn3P4, so that you have 6atoms of Sn on the left and 6 atoms of Sn on the right, same with the P
Answer:
V = 2600ms⁻¹
Explanation:
Given parameters:
Wavelength(λ) = 13meters
Period (T) = 0.005s
Period(T) is the time it takes for a full cycle of vibration to pass through. It's unit is in seconds (s)
The Velocity of waves is expressed as:
V = fλ
Where f = frequency(s⁻¹)
Frequency of a wave is the number of waves that passes through a point per unit time
f = 1/T
Where T is the period
We can therefore express Velocity of waves as a function of period
V = λ/T
Inputing the parameters, we have:
V = 13m / 0.005s
V = 2600ms⁻¹
Answer:
The correct answer is B.
The 
is samller than 
of the reaction . So,the reaction will shift towards the left i.e. towards the reactant side.
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.
For the given chemical reaction:
The expression for is written as:
![Q=\frac{[PCl_3][Cl_2]}{[[PCl_5]^1}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7B%5B%5BPCl_5%5D%5E1%7D)
Given : = 0.0454
Thus as 
, the reaction will shift towards the left i.e. towards the reactant side.
Answer:
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In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.
Explanation:
