Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
Answer:
D. 118°
Step-by-step explanation:
x = 118° { being corresponding angles }
Answer:
X[bar]= 115
Step-by-step explanation:
Hello!
Every Confidence interval to estimate the population mean are constructed following the structure:
"Estimator" ± margin of error"
Wich means that the intervals are centered around the sample mean. To know the value of the sample mean you have to make the following calculation:
![X[bar]= \frac{Upper bond + Low bond}{2}](https://tex.z-dn.net/?f=X%5Bbar%5D%3D%20%5Cfrac%7BUpper%20bond%20%2B%20Low%20bond%7D%7B2%7D)
![X[bar]= \frac{115.6+114.4}{2}](https://tex.z-dn.net/?f=X%5Bbar%5D%3D%20%5Cfrac%7B115.6%2B114.4%7D%7B2%7D)
= 115
Since both intervals were calculated with the information of the same sample, you can choose either to calculate the sample mean.
I hope it helps!
Answer:
4
Step-by-step explanation:
The x coordinate is the same so the distnce is only the difference in y
5 - 1 = 4
Answer:
y = 9.75
Step-by-step explanation:
Since both triangles are said to be similar, the proportion or ratio of the sides of both triangles would be equal.
Therefore, 39/y = 23/5.75 = 35/8.75
Let's find y
39/y = 23/5.75
==>Cross multiply
39*5.75 = 23*y
224.25 = 23y
==>Divide both sides by 23
224.25/23 = y
9.75 = y
y = 9.75
Check:
Thus,
39/9.75 = 23/5.75 = 35/8.75 = 4
Our answer y, which is 9.75, is correct.
