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aleksley [76]
3 years ago
15

Please help me with questions 43, 44, and 45

Chemistry
1 answer:
ohaa [14]3 years ago
6 0
Im que se puede encontrar un segundo lugar en a las que se puede hacer un trabajo en la it was correct but i said that he would not answer the answer
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A chemist must dilute 97.1 ml of aqueous magnesium fluoride solution until the concentration falls to 389 microMolarity . He'll
mojhsa [17]

Answer:

0.302L

Explanation:

<em>...97.1mL of 1.21m M aqueous magnesium fluoride solution</em>

<em />

In this problem the chemist is disolving a solution from 1.21mM = 1.21x10⁻³M, to 389μM = 389x10⁻⁶M. That means the solution must be diluted:

1.21x10⁻³M / 389x10⁻⁶M = 3.11 times

As the initial volume of the original concentration is 97.1mL, the final volume must be:

97.1mL * 3.11 = 302.0mL =

0.302L

6 0
3 years ago
Except for the reaction between iron and sulfur, none of the reactions in this
Sloan [31]

he total number of each of the atoms on the left and the right are the same thus the reaction equation is balanced.

<h3>What is the law of conservation of mass?</h3>

The law of conservation of mass states that, mass can neither be created nor destroyed. In view of the law of conservation of mass, the total mass of the reactants on the left-hand side must be the same as the total mass of products at the right hand side.

Thus is the total mass of the reactants and the products are not the same, it then follows that the reaction does not demonstrate the law of conservation of mass. In this case, the total number of each of the atoms on the left and the right are the same thus the reaction equation is balanced.

Learn more about conservation of mass:brainly.com/question/13383562

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4 0
1 year ago
chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode
Eduardwww [97]

chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode There is a difference of -0.786 V in silver

<h3>What is cell voltages ?</h3>

The difference in electric potential between two points, also known as voltage, electric potential difference, electric pressure, or electric tension, is what determines how much labor is required to move a test charge between the two sites in a static electric field. Volt is the name of the derived unit for voltage (potential difference) in the International System of Units. Joules per coulomb, or 1 volt equals 1 joule (of work) for 1 coulomb, is how work per unit charge is stated in SI units (of charge). The quantum Hall and Josephson effect was first employed in the 1990s, and most recently (in 2019), fundamental physical constants have been added for the definition of all SI units and derived units. Power and current were used in the previous SI definition for volt.

To learn more about  cell voltages from the given link:

brainly.com/question/18938125

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7 0
2 years ago
If a system has a reaction quotient of 2.13 ✕ 10−15 at 100°C, what will happen to the concentrations of COBr2, CO, and Br2 as th
qaws [65]

This is an incomplete question, here is a complete question.

Consider the following equilibrium at 100°C.

COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)

K_c=4.74\times 10^4

Concentration at equilibrium:

[COBr_2]=1.58\times 10^{-6}M

[Co]=2.78\times 10^{-3}M

[Br_2]=2.51\times 10^{-5}M

If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?

Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)

The expression for reaction quotient will be :

Q=\frac{[CO][Br_2]}{[COBr_2]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}

The given equilibrium constant value is, K_c=4.74\times 10^4

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K_c that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K_c that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the Q that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.

Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

3 0
3 years ago
6. What is a polyatomic ion? (You should also memorize the name, formula, and charge of the polyatomic ions listed in the lectur
strojnjashka [21]
A polyatomic ion is a group of elements that has a charge that is not 0. for example the charge of P04 is -3 
6 0
3 years ago
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