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Serjik [45]
3 years ago
9

Quick Help 10 points

Chemistry
2 answers:
Alenkasestr [34]3 years ago
6 0
D - matter remains constant in any chemical equation, so reactants always equal products.
Savatey [412]3 years ago
6 0

Answer:

The products will have one S and four O atoms.

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If the distance between a point charge and a neutral atom and is multiplied by a factor of 5, by what factor does the force on t
dexar [7]

Given :

The distance between a point charge and a neutral atom and is multiplied by a factor of 5.

To Find :

By what factor does the force on the neutral atom by the point charge change.

Solution :

We know, electrostatic force between two object is directly proportional to product of charge and inversely proportional to distance between them.

Now, charge in neutral atom is 0 C.

So, the electrostatic force between two of them is also 0 N.

Therefore, by changing distance between the charge the forces did no change ( it remains zero).

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3 years ago
Solutions of potassium iodide and lead(II)nitrate are mixed. The resulting lead
LenaWriter [7]
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Balance the equation
6 0
2 years ago
This question is about elements, compounds and mixtures.
Ede4ka [16]

Answer:

answer is potasium means k

6 0
3 years ago
Read 2 more answers
What is metal made out of?
maxonik [38]

Explanation:

Scientifically speaking, metals are naturally occurring chemical elements that are typically hard, lustrous, and good conductors of both heat and electricity. Examples include iron, gold, silver, copper, zinc, nickel, etc., but also elements we don't normally think of as metals.

7 0
3 years ago
When 3.0 kg of water is warmed from 10 °C to 80 °C, how much heat energy is needed?
Naddik [55]

Answer:

THE HEAT NEEDED TO CHANGE 3KG OF WATER FROM 10 C TO 80 C IS 877.8kJ OR 877,800 J.

Explanation:

Mass = 3.0 kg = 3 * 1000 = 3000 g

Initial temperature = 10 C

Final temperature = 80 C

Change in temperature = 80 - 10 = 70 C

Specific heat of water = 4.18 J/g C

Heat needed = unknown

Heat is the amount of energy in joules needed to change a gram of water by 1 C.

Heat = mass * specific heat * change in temperature

Heat = 3000 g * 4.18 J/g C * 70 C

Heat = 877 800 Joules

Heat = 877.8 kJ.

The heat needed to change 3 kg mass of water from 10 C to 80 C is 877,800 J or 877.8 kJ.

6 0
3 years ago
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