A 100 kg cart on a roller coaster has 1800J of kinetic energy. How fast is it going? KE= 1/2mv2

How can you measure the strength of any electric field?

Softa [21]

Answer:

The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.

Explanation:

Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.

7 0

3 years ago

In the parts that follow select whether the number presented in statement A is greater than, less than, or equal to the number p

OleMash [197]

Answer:

1) A> B, 2) A = B, 3) A> B

Explanation:

When a figure is given the number of significant figures to determine the precision or uncertainty the number

1) the uncertainty in the number with three significant figures is less than the number with two significant figures

statement A 2.6

statement B 2.57

A> B

2) decalration A

2,567 + 3,146 = 5,713

with two figures it remains

5.7

statement B

2.6 + 3.1 = 5.7

A = B

3) for the product the result is with the number that has the least significant figures

statement A

rectangles area

2.536 * 1.4 = 3.6

statement B

2.536 * 1.41 = 3.58

A> B

7 0

3 years ago

A plane flies along a straight line path after taking off, and it ends up 90.0 km farther

givi [52]

Answer:

east

Explanation:

4 0

3 years ago

Define distance and displacement with illustration

Deffense [45]

Answer:

<h2>Distance</h2>

The length of the actual path travelled by a body is called distance travelled by a body.It is a scalar Quantity.It is measured in meter(m) in SI system.

<h2>Displacement</h2>

The shortest distance from initial position to the final position of a body is called displacement of the body.It is a vector Quantity.It is measured in meter(m) in SI system..

Please see the attached picture...

It is the example of distance and displacement....

Hope this helps...

Good luck on your assignment...

3 0

3 years ago

Puck 1 is moving 10 m/s to the left and puck 2 is moving 8 m/s to the right. They have the same mass, m.

Julli [10]

Answer:

(a) the total momentum of the system before the collision = -2m kg.m/s.

(b) the total momentum of the system after the collision = -2m kg.m/s.

(c) puck 1's velocity after the collision in component form = (5.44 i, 2.54 j)

Explanation:

Given;

mass of Puck 1 , = m

mass of Puck 2, = m (since they have the same mass m)

initial velocity of Puck 1, u₁ = 10 m/s to the left

initial velocity of Puck 2, u₂ = 8 m/s to the right

Let the rightward direction be positive direction

Let the leftward direction be negative direction

(a) the total momentum of the system before the collision;

P₁ = (initial momentum of Pluck 1) + (initial momentum of Pluck 2)

P₁ = (-mu₁) + mu₂

P₁ = mu₂ - mu₁

P₁ = m(u₂ - u₁)

P₁ = m(8 - 10)

P₁ = -2m kg.m/s

(b) the total momentum of the system after the collision;

Based on the principle of conservation of linear momentum, the total momentum before collision is equal to the total momentum after collision.

Thus, the total momentum of the system after the collision is -2m kg.m/s.

(c) puck 1's velocity after the collision in component form

$v = (v_x, v_y)\\\\v = (vcos \theta , vsin \theta)\\\\v = (6cos 25^0 , 6sin25^0)\\\\v = (5.44i, 2.54j)m/s$

8 0

3 years ago