Answer:
A) a scientific theory or principle
Explanation:
A Theory or principle has to explain different observations for a specific phenomenon. Theories are tested in base of new data to see if they can fit with all the new variations. They gain more acceptance in the scientific world if they predict in a correct way the result of many observations.
For example the uncertainty principle which state that the position and the momentum of a particle can not be known at the same time. Many experiments that aim to test the Uncertainty principle demonstrated this property, but tests are currently being done with other variations to see if the principle still fits with them.
Answer:
Explanation:
Given that
Volume flow rate ,Q= 1200 m³ each seconds
So we can say that
Q= 1200 m³ /s
From energy conservation
(Potential energy +kinetic energy ) at top = (Potential energy +kinetic energy ) at bottom
U₁+ KE₁ = U₂+ KE₂
ρ Q g h + 0 = 0 + KE₂
KE₂= ρ Q g h
For water ,ρ = 1000 kg/m³
KE₂=1000 x 1200 x 10 x 100 W ( take g= 10 m/s²)
KE₂=120 x 10⁷ W
Only three forth of the energy converted into electrical energy
Therefore power P
Answer:
B. Solid rock breaks apart.
Explanation:
Answer:
No acceleration. All of the forces are acting equally on the paper air plane therfore It isn't going to move any where.
Answer:
M = 0.31 kg
Explanation:
This exercise must be done in parts, let's start by finding the speed of the set arrow plus apple, for this we define a system formed by the arrow and the apple, therefore the forces during the collision are internal and the moment is conserved
let's use m for the mass of the arrow with velocity v₁ = 20.4 m / s and M for the mass of the apple
initial instant. Just before the crash
p₀ = m v₁ + M 0
instant fianl. Right after the crash
p_f = (m + M) v
p₀ = p_f
m v₁ = (m + M) v
v = (1)
now we can work the arrow plus apple set when it leaves the child's head with horizontal speed and reaches the floor at x = 8 m. We can use kinematics to find the velocity of the set
x = v t
y = y₀ + t - ½ g t²
when it reaches the ground, its height is y = 0 and as it comes out horizontally,
0 = h - ½ g t²
t² = 2h / g
For the solution of the exercise, the height of the child must be known, suppose that h = 1 m
t =
t = 0.452 s
let's find the initial velocity
v = v / t
v = 8 / 0.452
v = 17.7 m / s
From equation 1
v = m / (m + M) v₁
m + M =
M = m + m \ \frac{v_1}{v}
we calculate
M = 0.144 + 0.144
M = 0.31 kg