m/s² aka meter per second squared.
acceleration = change in velocity/time
= distance/time
--
time
= m/s
--
s
=m/s^2
Explanation:
The hydrological cycle is the continuous cycling of water between land, open water surfaces and the sea. This cycle begins with evaporation, sunlight evaporates water from the surface of earth, next condensation happens, the water absorbed is now used to form clouds, after these clouds are filled to the maximum, precipitation happens, this can be in the form of rainfall and snow, this cycle finalizes when the precipitation of water runs off the land and back into water sources.
Sources of water pollution:
- <em>During precipitation: </em>Smog can be gathered in the atmosphere, during precipitation this pollution can turn into acid rain.
- <em>During runoff:</em> After acid rain hits the ground this polluted water can run into water sources (lakes, rivers, reservoirs).To some extent rivers are a self-renewing resource, if a small quantity of pollution discharges in it the river can return to a clean, unpolluted condition, unfortunately, if the pollution is too big the renewing won't be possible, another problem is even though rivers get cleaned the pollution moves to the seas. Lakes are even more vulnerable to pollution, the flushing effect in these water bodies is less evident than in rivers.
I hope you find this information useful and interesting! Good luck!
1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)
=> p1 = 2 p2
Which is easy to demonstrate using ideal gas equation:
p1 = nRT/V = 2.0 mol * RT / 1 liter
p2 = nRT/V = 1.0 mol * RT / 1 liter
=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2
2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.
So, the pressure in both chambers (which form one same vessel) is:
p = nRT/V = 3.0 mol * RT / 2liter
which compared to the initial pressure in chamber 1, p1, is:
p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1
So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.
You can also see how the pressure in chamber 2 changes:
p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.
Answer:
Explanation:
So, the formula for the compound should be:
Now we assume that we have 1 mol of substance, so we can make calculations to know the molar mass of element X, as follows:
So we have that 6 moles weight 212.7g, and we can make a rule of three to know the weight of compound X:
As we used 1 mol, we know that the molar mass is 32.06g/mol
So the element has a molar mass of 32.06 g/mol and an oxidation state of +6, with this information, we can assure that the element X is sulfur, so the compound is 
